What is the missing number that will complete the factorization? 6 8 12 24.

Mathematics

1 answer:

gregori [183]1 year ago

3 0

The missing number or factor which can replace the question mark will be 6.

The given table is:

a ?

a $a^2$ 6a

2 2a 12

It is required to find the factor which will replace the question mark.

<h3>How to find the missing number or factor?</h3>

In the first row, the factor is a. So, after diving a from the row, the remaining part will be,

a and 6.

Now, in the second row, the factor is 2. So, after diving 2 from the row, the remaining part or quotient will be,

a and 6.

In the second column, 6 is remained after diving by the row factor.

Therefore, the missing number or factor which can replace the question mark will be 6.

For more details about factors, refer to the link;

brainly.com/question/6810544

You might be interested in

The numbers 2/1/3,h,k,7/7/8 firm a geometric progression. find the value of h and of k

taurus [48]

$\text{We have }\ 2\dfrac{1}{3},\ h,\ k,\ 7\dfrac{7}{8}.\\\\\text{Convert the mixed numbers to the improper fractions}\\\\2\dfrac{1}{3}=\dfrac{2\cdot3+1}{3}=\dfrac{7}{3}\\\\7\dfrac{7}{8}=\dfrac{7\cdot8+7}{8}=\dfrac{63}{8}\\\\\text{If}\ a_1,\ a_2,\ a_3,\ a_4\ \text{is a geometric seqence, then:}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=r\\\\a_2=a_1r\\\\\text{and}\ \dfrac{a_4}{a_1}=r^3\\\\\text{Substitute:}$

$r^3=\dfrac{\frac{63}{8}}{\frac{7}{3}}\\\\r^3=\dfrac{63}{8}\cdot\dfrac{3}{7}\\\\r^3=\dfrac{9\cdot3}{8\cdot1}\\\\r^3=\dfrac{27}{8}\to r=\sqrt[3]{\dfrac{27}{8}}\\\\r=\dfrac{3}{2}\\\\h=2\dfrac{1}{3}\cdot\dfrac{3}{2}=\dfrac{7}{3}\cdot\dfrac{3}{2}=\dfrac{7}{2}\\\\k=\dfrac{7}{2}\cdot\dfrac{3}{2}=\dfrac{21}{4}\\\\Answer:\ \boxed{h=\dfrac{7}{2}=3\dfrac{1}{2}\ and\ k=\dfrac{21}{4}=5\dfrac{1}{4}}$