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spin [16.1K]
3 years ago
8

What f(5) if f(x) = -2x +1

Mathematics
1 answer:
Effectus [21]3 years ago
5 0
F(5) is like X is 5
you just do this 
f(5)=-2x+1
     =-2(5)+1
     =-10+1
     = -9

:D
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I need help please answer these two questions for me! Will give points.​
jarptica [38.1K]

Answer:

7.) 7

10.)  0

Step-by-step explanation:

When it means "evaluate the function", it's in essence asking us to see what the function spits out when we feed it a certain input. Our inputs are our x values, which spit out a y value.

Evaluating the function when x = 1:

Let's look at where the function has an x value of 1. We see it near the bottom of the table and see the y value associated with the input is 7. So when the function is fed 1 as an input, it spits out 7.

Evaluating the function when f(x) = - 2:

This one is a weird because of the new notation. Just think of it as some value of f, which we don't know (so we represent it as an x-variable) must equal -2. So let's look at our table to find out where our output is -2. We find that when f(x) = -2 the input is 0. So the input which gives -2 is 0.

7 0
3 years ago
Which product is positive?<br>​
Tresset [83]

Answer:

The last option.

Step-by-step explanation:

When you multiply a negative by a negative it makes a positive number. Therefore, if you multiply an even number of negative numbers, you get a positive product. The other options have an odd number of negative numbers to multiply by that makes them result in a negative product.

6 0
3 years ago
What is the vertex of the graph of y=2(x+6)^2-2
daser333 [38]

Answer:

the vertex is 4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Please help asap! explaining how you got the answer will give you brainliest.
xeze [42]
It would be 6 because the other short side is 6 so it should be 6 units
7 0
3 years ago
Solve for y2<br><br> m= y2-y1 / x2-x1
Alex Ar [27]
M=(y2-y1)/(x2-x1) <em>(Multiplied terms on both sides of equation by (x2-x1).)</em>

m(x2-x1)=y2-y1 <em>(Added y1 to both sides of equation, ultimately isolating y2.)</em>

y2=m(x2-x1)+y1
5 0
3 years ago
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