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aleksklad [387]
1 year ago
11

Explain how impurities are selected for doping in group 14 semiconductors

Chemistry
1 answer:
aleksklad [387]1 year ago
6 0

Impurities selection for doping in group 14 semiconductors is: based on their ability to add more holes and fewer electrons or to add more electrons and reduce the holes.

<h3>Meaning of Semiconductors</h3>

Semiconductors can be defined as any material that has the ability to exhibit some properties of a conductor and some properties of an insulator.

A semiconductor can be used as either a conductor or an insulator when worked upon.

In conclusion, Impurities selection for doping in group 14 semiconductors is: based on their ability to add more holes and fewer electrons or to add more electrons and reduce the holes.

Learn more about semiconductors: brainly.com/question/1918629

#SPJ1

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How many hydrogen atoms are in 1.50 x 10(22) molecules of water. Show your work.
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What is the wavelength (nm) of radiation that has an energy content of 1.27*10^3 kj/mol?
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3 years ago
A quantity of 7.480 g of an organic compound is dissolved in water to make 300.0 mL of solution. The solution has an osmotic pre
Serga [27]

Answer:

C5H6N2O3

Explanation:

First the empirical formulas

C= 41.8÷12= 2.48

H= 4.7÷1= 4.7

O= 37.3÷ 16= 2.33

N= 16.3÷14 = 1.16

Divide by the smallest

C= 3.48/1.16=3

H= 4.7/1.16=4.1

O= 2.33/1.16=2

N= 1.16/1.16=1

Therefore empirical formula = C3H4NO2

To calculate molecular formula for osmotic pressure,

π= cRT

Or

π=cgRT/M where cg is in g/liter & T is temperature in Kelvin. Thus

π= (7.480*0.0821*300)/ M

M= 184.23/1.43

M= 128.83

To find molecular Formula

Molecular Mass= (empirical mass)n

128.83= (C3H4NO2)n

128.83= 86n

n= 1.5

Therefore the molecular formula

(C3H4NO2)1.5

= C4.5H6N1.5O3

Approximately

C5H6N2O3

7 0
3 years ago
How many kilojoules of heat are absorbed when 1.00 L of water is heated from 18°C to 85°C? (Specific heat capacity of water is 4
lord [1]

ANSWER: 280.06 kilojoules.

EXPLANATION:

Heat absorbed can be calculated from the equation Q = m . C . ΔT

where m = mass of substance in grams

C = specific heat capacity of substance in J/g°C

ΔT = temperature difference.

So, to calculate heat absorbed by water we must know three terms, mass of water, specific heat capacity of water and temperature difference.

Have a look at question, Specific heat capacity of water, C = 4.18 J/g°C..                                 Temperature difference is, ΔT = (85 - 18) °C = 67 °C.                                                                 Mass of water is not given, instead we are given volume of water = 1 L and density of water = 1 g/mL. So we need to calculate mass of water from volume and density.

We know the formula, density is mass upon volume. see pic for calculation. mass of water comes out to be 1000 g.

So, now we know m = 1000 g, C = 4.18 J/g°C and ΔT = 67 °C.

Use, Q = m . C . ΔT to calculate heat absorbed.

Q = 1000 g . 4.18 J/g°C . 67 °C  = 280060 J.

The answer comes out be in units of Joules but we need answer in kilojoules so divide the answer by 1000(thousand).

answer will be 280.06 kilojoules.


4 0
3 years ago
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