Answer:
The heat absorbed by water is 39243.75 J.
Explanation:
Given data:
Mass of water = 375.0 g
Heat absorbed by water= ?
Initial temperature = 10.0°C
Final temperature = 35.0 °C
The specific heat capacity of water = 4.186 j/g.°C
Solution:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 35°C - 10°C
ΔT = 25°C
Q = m.c. ΔT
Q = 375.0 g× 4.186 j/g °C × 25°C
Q = 39243.75 J
The heat absorbed by water is 39243.75 J.
Answer:
A, C, and D
Explanation:
A-Any type of rock can change into any other type of rock by weathering and erosion.
C-Rocks change slowly over time.
D- The rock cycle shows how the three rock types relate to one another.
Its correct on edge
Answer:
31.345 cm³
Explanation:
Given:
Mass of the empty flask, m = 56.12 g
Mass of the flask filled with water, M = 87.39 g
Density of the water, ρ = 0.9976 g/cm³
now,
the mass of water filled in the flask, Mw = M - m = 87.39 - 56.12 = 31.27 g
also,
Density = mass / volume
thus, for water
0.9976 = 31.27 / volume
or
volume of water = 31.345 cm³
hence, the volume of flask is the volume of water filled = 31.345 cm³
It is important to make sure the solvent is level and not at an angle so you do not get an angled solvent front.
