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Musya8 [376]
2 years ago
9

which of the following pairs of molecules can form hydrogen bonds between them? group of answer choices ch3oh and nh3 hcl and hi

ch4 and h2o fo2 and ch2o h2 and o2
Chemistry
1 answer:
Alik [6]2 years ago
5 0

Answer:

Hydrogen Bond is the force that exists when H is directly connected to F, O, or N. HCl and HI cannot form hydrogen bonds between them. CH3OH and NH3 can form hydrogen bonds between them. CH4 and H2O cannot form hydrogen bonds between them.

Explanation:

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Which is the smallest number?
My name is Ann [436]

Answer:

What I came up with was D equaling out to be 42

Explanation:

Im assuming you just do the math

A. 3.5 x 104 = 364

B. 2.4 x 103 = 247.2

C. 1.4 x 10^2_2 = 280

D. 4.9 x 10-7 = 42

I hope I helped.

5 0
3 years ago
A particular first-order reaction has a rate constant of 1.35 × 102 s-1 at 25.0°C. What is the magnitude of k at 95.0°C if Ea =
never [62]

Answer:

k ≈ 9,56x10³ s⁻¹

Explanation:

It is possible to solve this question using Arrhenius formula:

ln\frac{k2}{k1} = \frac{-Ea}{R} (\frac{1}{T2} -\frac{1}{T1} )

Where:

k1: 1,35x10² s⁻¹

T1: 25,0°C + 273,15 = 298,15K

Ea = 55,5 kJ/mol

R = 8,314472x10⁻³ kJ/molK

k2 : ???

T2: 95,0°C+ 273,15K = 368,15K

Solving:

ln\frac{k2}{k1} = 4,257

\frac{k2}{k1} = 70,593

{k2} = 9,53x10^3 s^{-1}

<em>k ≈ 9,56x10³ s⁻¹</em>

I hope it helps!

5 0
3 years ago
How many moles are in 8.63 x 103 atoms of Li?
Ira Lisetskai [31]
<h3>Answer:</h3>

1.43 × 10⁻²⁰ mol Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

8.63 × 10³ atoms Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 8.63 \cdot 10^3 \ atoms \ Li(\frac{1 \ mol \ Li}{6.022 \cdot 10^{23} \ atoms \ Li})
  2. Multiply/Divide:                \displaystyle 1.43355 \cdot 10^{-20} \ moles \ Li

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li

4 0
2 years ago
How many grams are in 6.53 moles of Pb
dezoksy [38]
Mr: 207.2
m=n×Mr= 6.53×207.2= 1353.02g
7 0
3 years ago
A chemistry instructor provides each student with 8 test tubes at the beginning of the year. If there are 28 students per class,
klemol [59]
Three classes: 28×3=84 students
8 test tubes per student: 84× 8= 672
hope this helps!
7 0
3 years ago
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