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3 years ago

Need quite a bit of help

Physics

1 answer:

Gnom [1K]3 years ago

3 0

When the cart was at Table

Normal reaction (N)=mg

Now acceleration due to gravity acting on the gravity.

When the air comes out of straw it tries to take the cart upwards.
But the force is equal to that of acceleration due to gravity but in opposite direction.

Hence.

$\\ \sf\Rrightarrow F_{net}=0N$

So the cart doesn't move

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A force of 100N is applied to an area of 100mm².what is the pressure exerted on the area in N/m².

Dmitry_Shevchenko [17]

Answer:

P = 1000000[Pa] = 1000 [kPa]

Explanation:

To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.

$P=F/A$

where:

P = pressure [Pa] (units of pascals)

F = force = 100 [N]

A = area = 100 [mm²]

But first we must convert the units from square millimeters to square meters.

$A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2} } =0.0001[m^{2} ]$

Now replacing:

$P=100/0.0001\\P=1000000[Pa]$

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3 years ago

Two objects gravitationally attract with a force of 100 N. If the mass of one object is doubled and the mass of the other object

barxatty [35]

Hello!

Recall the equation for gravitational force:
$F_g = \frac{Gm_1m_2}{r^2}$

Fg = Force of gravity (N)
G = Gravitational constant

m1, m2 = masses of objects (kg)
r = distance between the objects' center of masses (m)

There is a DIRECT relationship between mass and gravitational force.

We are given:
$F_g = 100N$

If we were to double one mass and triple another, according to the equation:
$F'_g = \frac{G(2m_1)(3m_2)}{r^2} = 6(\frac{G(m_1)(m_2)}{r^2}) = 6F_g$

Thus:
$6 * F_g = 6 * 100 = \boxed{600N}$

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A parallel plate capacitor is constructed using two square metal sheets, each of side L = 10 cm. The plates are separated by a d

Snowcat [4.5K]

Answer:

The energy stored is 1.4 x 10^-9 J.

Explanation:

Side of square, L = 10 cm = 0.1 m

Distance, d = 2 mm = 0.002 m

Electric field, E = 4000 V/m

The energy stored in the capacitor is

$U = 0.5 C V^2$

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