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nadezda [96]
2 years ago
11

Any tips on how to get a good grasp of physics and chemistry?

Physics
1 answer:
Helga [31]2 years ago
4 0

Answer: Take notes and research into the subject more get extra help like tutoring if needed.

Explanation: ...

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At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh
Anna35 [415]

We have the equation for electric field E = kQ/d^{2}

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to d^{2}

So, \frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

E_{1} = 485 N/C

d_{1} = 0.208 cm

d_{2} = 0.620 cm

E_{2} = ?

\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}

E_{2} = \frac{485*0.208^{2}}{0.628^{2}}

E_{2} = 53.20 N/C

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3 years ago
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In and electric circuit, where do the electrons come from that flow in the circuit
Firdavs [7]
The electrons are already there. They are freely moving through the conductor.
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3 years ago
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What happens to the speed of light as it passes into a glass block?
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➷ The speed would reduce as glass is denser than air.

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3 years ago
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Need some help with these two physics problems!
Juliette [100K]

The force that keeps the puck moving is 0.25 N while the velocity of the puck is  3.7 m/s.

<h3>What is the centripetal force?</h3>

We know that the centripetal force is the force that acts on a body that is moving along a circular path. In this case, we are told that the puck is moving along a circular path hence it is acted upon by the centripetal force that acts on it.

The centripetal force in this case would be supplied by the weight of the object that is moving in the circular path. Thus we can write in our equation that;

Centripetal force = Weight of object = mg

m = mass of the object

g = acceleration due to gravity

Then;

W = 0.026 Kg * 9.8 m/s^2

W = 0.25 N

To obtain the velocity of the object;

FT = mv^2/r

v = √ FT r/m

v =  √0.25 * 1.4/0.026

v = 3.7 m/s

Learn more about centripetal force:brainly.com/question/11324711

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5 0
1 year ago
When operated on a household 110.0-V line, typical hair dryers draw about 1650 W of power. We can model the current as a long st
defon

Answer:

Current in the hair dryer will be equal to 15 A

Explanation:

We have given that household is operated at 110 volt

So potential difference V =110 volt

Power drawn by hairdryer is P = 1650 watt

We have to find the current in the hair dryer

We know that power is given as P = VI, here V is potential difference and I is current

So 1650=110\times I

I = 15 A

So current in the hair dryer will be equal to 15 A

4 0
3 years ago
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