A strip of copper metal is riveted to a strip of aluminum. the two metals are then heated. the coefficient of linear expansion o
1 answer:
You might be interested in
Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.
Answer:
D = -4/7 = - 0.57
C = 17/7 = 2.43
Explanation:
We have the following two equations:
First, we isolate C from equation (2):
using this value of C from equation (3) in equation (1):
<u>D = - 0.57</u>
Put this value in equation (3), we get:
<u>C = 2.43</u>