Question

A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frictional force that acts on the puck?

Answer 1

Answer:

The frictional force is  $F_f = 1.75 \ N$

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  $F_N = 5 \ N$

Generally the frictional force that acts on the puck is mathematically represented as

          $F_f = \mu_k * F_N$

=>       $F_f = 0.35 * 5$

=>       $F_f = 1.75 \ N$