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olga_2 [115]
3 years ago
6

A hockey puck has a coefficient of kinetic friction of μk = .35. If the puck feels a normal force (FN) of 5 N, what is the frict

ional force that acts on the puck?
Physics
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

The frictional force is  F_f =  1.75 \  N

Explanation:

From the question we are told that

     The coefficient of kinetic force is  μk = 0.35

     The normal force felt by the puck is  F_N  =  5 \  N

Generally the frictional force that acts on the puck is mathematically represented as

          F_f =  \mu_k  *  F_N

=>       F_f =  0.35  *  5

=>       F_f =  1.75 \  N

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2 years ago
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3 years ago
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