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stepladder [879]

3 years ago

6

San Jose to San Francisco is approximately 7200 meters away. If it takes you 3600 seconds to drive by car what is the velocity?

Make sure to include the correct units.

1 answer:

svetlana [45]3 years ago

5 0

V=s/t=>7200/3600=2m/s

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Beings on spherical asteroid have observed that a large rock is approaching their asteroid in a collision course. At 7514 km fro

luda_lava [24]

Answer:

c. $4.582\times10^{21} kg$

Explanation:

$r_{i}$ = Initial distance between asteroid and rock = 7514 km = 7514000 m

$r_{f}$ = Final distance between asteroid and rock = 2823 km = 2823000 m

$v_{i}$ = Initial speed of rock = 136 ms⁻¹

$v_{f}$ = Final speed of rock = 392 ms⁻¹

$m$ = mass of the rock

$M$ = mass of the asteroid

Using conservation of energy

Initial Kinetic energy of rock + Initial gravitational potential energy = Final Kinetic energy of rock + Final gravitational potential energy

$(0.5) m v_{i}^{2} - \frac{GMm}{r_{i}} = (0.5) m v_{f}^{2} - \frac{GMm}{r_{f}} \\(0.5) v_{i}^{2} - \frac{GM}{r_{i}} = (0.5) v_{f}^{2} - \frac{GM}{r_{f}} \\(0.5) (136)^{2} - \frac{(6.67\times10^{-11}) M}{(7514000)} = (0.5) (392)^{2} - \frac{(6.67\times10^{-11}) M}{(2823000)} \\M = 4.582\times10^{21} kg$

8 0

3 years ago

What happens when you compress a gas?

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The density increases.
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P×V ~ T

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3 years ago

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Carol can be defined as a social drinker because she can easily limit drinking and she chiefly drinks alcohol when she is out wi

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True. These are the characteristics of a social drinker.

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Two capacitors, a 15 micro F and a 25 micro F, are connected in parallel to a 60 Hz source. The total capacitive reactance is :_

Stells [14]

Answer:

<em> 3980.89 ohms</em>

Explanation:

The capacitive reactance is expressed as;

$X_c = \frac{1}{2 \pi fC}$

f is the frequency

C is the capacitance of the capacitor

Given

f = 60H

C = C1+C2 (parallel connection)

C = 15μF + 25μF

C = 40μF

C = $40 * 10^{-6}F$

Substitute into the formula:

$X_c = \frac{1}{2(3.14)*60*40*10^{-6}}\\X_c = \frac{1}{0.0002512}\\X_c = 3,980.89$

<em>Hence the total capacitive reactance is 3980.89 ohms</em>

5 0

3 years ago

You throw a glob of putty straight up toward the ceiling, which is 3.50 mm above the point where the putty leaves your hand. The

LuckyWell [14K]

Answer: $4.65\ m/s$

Explanation:

Given

Distance putty has to travel is 3.5 m

The initial speed of putty is 9.50 m/s

Using equation of motion to determine the velocity of putty just before it hits ceiling

$v^2-u^2=2as$

$\Rightarrow v^2-(9.5)^2=2(-9.8)(3.5)\\\\\Rightarrow v^2=9.5^2-68.6\\\Rightarrow v=\sqrt{90.25-68.6}\\\Rightarrow v=4.65\ m/s$

So, the velocity of putty just before hitting is $4.65\ m/s$

5 0

3 years ago