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3 years ago

Which of the following chemical equations is balanced?

Chemistry

2 answers:

IRINA_888 [86]3 years ago

7 0

Answer:

Option d. Zn + 2HCI –> ZnCl2 + H2

Explanation:

First let us generate a balanced equation to know which of the above is balanced.

This is illustrated below:

Zn + HCl —> ZnCl2 + H2

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl a shown below:

Zn + 2HCl —> ZnCl2 + H2

Now we can see clearly that the equation is balanced as there are equal numbers of atoms of the different elements present on both sides of the equation.

Now let us check for the above equation in the options given in question.

xxTIMURxx [149]3 years ago

4 0

Answer:

Explanation:

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Help me please thanks

Evgesh-ka [11]

Then answer would be D. Answer D is correct because you would need to use a better solvent to see the ink separate on the chromatography paper. Hope that helps. :)

6 0

3 years ago

3. Ammonia, NH3, is a typical ingredient in household cleaners. It is produced through a combination reaction involving N2(g) an

hram777 [196]

N2 + 3H2 ----> 2NH3

you can see 3 moles H2 reacts to form 2 moles NH3 
Therefore moles NH3 = 2 / 3 x moles H2 
= 2/3 x 12.0 mol 
= 8.00 mol NH3 hope this help

6 0

3 years ago

Read 2 more answers

Select the correct answer. When an atom in a reactant loses electrons, what happens to its oxidation number? A. Its oxidation nu

vfiekz [6]

Answer:

C. Its oxidation number increases.

Explanation:

Oxidation is defined as the loss of electrons by an atom while reduction is the gain of electrons by an atom.
Atoms of elements have an oxidation number of Zero in their elemental state.
When an atom looses electrons it undergoes oxidation and its oxidation number increases.
For example, an atom of sodium (Na) at its elemental state has an oxidation number of 0. When the sodium atom looses an electrons it becomes a cation, Na+, with an oxidation number of +1 , the loss of electron shows an increase in oxidation number from 0 to +1.

8 0

2 years ago

Read 2 more answers

What is Kb for CH3NH2(aq) + H2O(1) CH3NH3(aq) + OH (aq)?

statuscvo [17]

Answer:

Kb for CH₃NH₂ (methylamine) is 4.4 × 10⁻⁴

Hope that helps.

8 0

3 years ago

Information-

tekilochka [14]

Answer:

So first thing to do in these types of problems is write out your chemical reaction and balance it:

Mg + O2 --> MgO

Then you need to start thinking about moles of Magnesium for moles of Magnesium Oxide. Based on the above equation 1 mole of Magnesium is needed to make one mole of Magnesium Oxide.

To get moles of magnesium you need to take the grams you started with (.418) and convert to moles by dividing by molecular weight of Mg (24.305), this gives you .0172 moles of Mg.

The theoretical yield would be the assumption that 100% of the magnesium will be converted into Magnesium Oxide, so you would get, based on the first equation, .0172 mol of MgO. Multiplying this by the molecular weight of MgO (24.305+16) gives us .693 g of MgO.

The percent yield is what you actually got in the experiment, and for this you subtract off the total mass from the crucible mass, or 27.374 - 26.687, which gives .66 g of MgO obtained.

Percent yield is acutal/theoretical, .66/.693, or 95.24%.

I'll let you do the same for the second trial, and average percent yield is just an average of the two trials percent yield.

Hope this helps.

6 0

3 years ago