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Ivahew [28]
3 years ago
8

Could I get some help, please?

Physics
1 answer:
tamaranim1 [39]3 years ago
8 0
I believe it’s D, all the others seem out of context.
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64 g of sulfur dioxide (SO2) contains 32 g of oxygen. Calculate how much sulfur it contains.
Ghella [55]
In sulfur dioxide, there are 2 oxygen atoms and 1 sulfur atom. As there are 32g of sulfur and 32g of oxygen, that would mean that each oxygen atom would weigh about 16g. Given that, the mass of a single sulfur atom is twice that of a single oxygen atom. 
5 0
3 years ago
Read 2 more answers
Which description matches up correctly with each type of particle? Alpha - no mass and no charge; beta - mass of 4 and charge of
Veseljchak [2.6K]
The closest answer is
Alpha - mass of 4 and charge of +2; beta - no mass and charge of -1; gamma - no mass and no charge (consists of energy)

It’s not exactly correct because a beta particle has the (small) mass of an electron (also the positron). All other choices are way off, I’d go with this one.
8 0
3 years ago
The mass of an electron is about 9.11 × 10-31 kg. Write this as a whole number
galina1969 [7]

Answer:

1 electron has a mass of 9.1 X 10-31 kg. How many electrons n does it take to make 1 kg?

(1 e)/(9.1 X 10-31 kg) = n/(1 kg)

So, n = 1.10 X 1030 electrons

Each electron has a charge of 1.6 X 10-19 C, where C stands for Coulombs. So, the n electrons have a charge of q = ne = (1.10 X 1030 electrons) X (1.6 X 10-19 C/electron) = 1.76 X 1011 C. This is an insane charge!

The electrostatic force between two of these 1kg bundles of electrons is given by Coulomb's law:

F = k qq/r2 = (8.99 X 109)(1.76 X 1011 C)2/(1000 m)2 = 2.78 X 1026 N.

7 0
3 years ago
Read 2 more answers
A beam of light is emitted 8.6 cm beneath the surface of a liquid and strikes the air surface 7.2 cm from the point directly abo
Makovka662 [10]

Answer:

n = 1.56

Explanation:

The total reflection attempts occurs when a light beam passes from a medium with a higher index to a medium with a lower nest, at an angle where it occurs we can find them by the refractive relationship

             n₁ sin θ₁ = n₂ sin θ₂

             n1 = n2 / sin θ₁

For this relationship to be fulfilled, the liquid index must be greater than the air index divided by the sine of the critical angle

Let's use trigonometry to find angle

               tan θ = y / x

                θ = tan⁻¹ 7.2 / 8.6

                θ = 39.94º

         

                n₁ = 1 / sin 39.94

                n = 1.56

This is the refractive index of the liquid

4 0
3 years ago
A 15 kg block is on a ramp which is inclined at 20o above the horizontal. It is connected by a string to a 19 kg mass which hang
12345 [234]

Answer:

The magnitude of the acceleration of the 19 kg block is 1.414 m/s²

Explanation:

From Newton's second law of motion;

F_{Net} = ma

where;

m is the mass of the objects involved, kg

a is the acceleration of the object, m/s²

different forces on the block and string

⇒force due to 15 kg block

=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396

= 138.12 N

⇒Tensional Force on 19 kg mass:

T = mg = 19×9.8 = 186.2 N

F_{Net} = T-mg = a(m_1+m_2)

186.2 - 138.12 = a(15+19)

48.08 =  a(34)

a = 48.08/34

a = 1.414 m/s²

Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²

7 0
4 years ago
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