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Sindrei [870]
4 years ago
9

A 15 kg block is on a ramp which is inclined at 20o above the horizontal. It is connected by a string to a 19 kg mass which hang

s over the top edge of the ramp. Assuming that frictional forces may be neglected, what is the magnitude of the acceleration of the 19 kg block
Physics
1 answer:
12345 [234]4 years ago
7 0

Answer:

The magnitude of the acceleration of the 19 kg block is 1.414 m/s²

Explanation:

From Newton's second law of motion;

F_{Net} = ma

where;

m is the mass of the objects involved, kg

a is the acceleration of the object, m/s²

different forces on the block and string

⇒force due to 15 kg block

=mgcosθ = 15×9.8×cos20 = 15×9.8×0.9396

= 138.12 N

⇒Tensional Force on 19 kg mass:

T = mg = 19×9.8 = 186.2 N

F_{Net} = T-mg = a(m_1+m_2)

186.2 - 138.12 = a(15+19)

48.08 =  a(34)

a = 48.08/34

a = 1.414 m/s²

Therefore, the magnitude of the acceleration of the 19 kg block is 1.414 m/s²

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Answer:

P = 5880  J

Explanation:

Given that,

The mass of the block, m = 30 kg

The block is sitting at a height of 20 m.

The block will have gravitational potential energy. The formula for gravitational potential energy is given by :

P=mgh\\\\=30\times 9.8\times 20\\\\=5880\ J

So, the required potential energy is equal to 5880  J.

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3 years ago
a 4050 N sled is being pushed with a force of 575 N. If it encounters a frictional force of 385 N… determine the net force
creativ13 [48]

According to the solving the net force is:

= 3,860.

<h3>Why is net force important?</h3>

The net force is the total of all the forces operating on an object, according to its definition. Mass can be accelerated by net force. Whether a body is at rest or in motion, another force is at work on it. When a system has a lot of forces acting on it, the phrase "net force" is employed.

<h3>What's the net force equation?</h3>

When a body is moving and multiple forces, such as the normal force, frictional force, and gravitational force, are acting on it, the combined effect is known as net force. As a result, is the net force formula. FNet equals Fa, Fg, Ff, and FN.

<h3>According to the given data:</h3>

4050 N sled

force of 575 N.

encounters a frictional force of 385 N

So the net force will be:

(Net)F = F₁ + F₂ + F₃

So,

(Net)F = F₁ + F₂ - F₃(frictional force)

(Net)F = 4050 + 385 - 575

= 3,860

According to the solving the net force is:

= 3,860.

To know more about net force visit:

brainly.com/question/18109210

#SPJ10

8 0
1 year ago
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