Answer:
Empirical formula = C₃S₂
Explanation:
Given data:
Mass of carbon = 44.0 mg (44/1000 = 0.044 g)
Mass of sulfur = 122 mg - 44.0 mg = 78 mg = 78/1000 = 0.078 g)
Empirical formula = ?
Solution:
First of all we will calculate the number of moles.
Number of moles of carbon = mass / molar mass
Number of moles of carbon = 0.044 g/ 12.01 g/mol
Number of moles of carbon = 0.0037 mol
Number of moles of sulfur:
Number of moles = mass / molar mass
Number of moles = 0.078 g/ 32,066 g/mol
Number of moles = 0.0024 mol
Now we will compare the moles:
C : S
0.0037/0.0024 : 0.0024/0.0024
1.5 : 1
C : S = 2(1.5 : 1)
C : S = 3 : 2
Empirical formula = C₃S₂
Imagine we have <span>mass of solvent 1kg (1000g)
According to that: </span>

= 4.8 mole * 98 g/mole = 470g


m(H2SO4) which is =<span>470g
</span><span>m(solution) = m(H2SO4) + m(solvent) = 470 + 1000 = 1470 g
d(solution) = m(solution) / V(solution) =>
=> 1.249 g/mL = 1470 g / V(solution) =></span>
Answer:
KOH
Explanation:
Chemical reaction:
2K + 2H₂O → 2KOH + H₂
Element ratio of K.
K = 1
Because only potassium is present.
Element ratio of H₂O.
2 : 1
in water ratio of element is 2 : 1 because two hydrogen and one oxygen atom present.
Element ratio of KOH
1 : 1 : 1
in KOH elemental ratio is 1 : 1 : 1 because one potassium one hydrogen and one oxygen atom are present.
Element ratio of H₂.
2
Just two atoms of hydrogen are present.
There are 21 atoms represented in the formula :) hope this helped.
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