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Andre45 [30]
3 years ago
15

If I have 72 liters of argon gas held at a pressure of 3.4 atm and a temperature of 225k how many grams of argon do I have

Chemistry
1 answer:
andrezito [222]3 years ago
5 0

Answer:

516.77 grams of Argon gas is present

Explanation:

Using the gas formula

PV = nRT

number of moles (n) = mass / molar weight or mass

P = pressure = 3.4 atm

V = volume = 72 L

R = gas constant = 0.082 L atm mol^-1 K^-1

T = temperature = 225 K

MM = molar mass of Ar = 38.984 g/mol

PV = mRT/ MM

m = PV MM / RT

m = 3.4 * 72 * 38.948 / 0.082 * 225

m =  9534.4704 / 18.45

m = 516.77 grams

the mass of Ar gas you have is 516.77 grams.

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pH + 11.24 = 14

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Answer:

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What mass of zinc is needed to react with 23.1g of phosphoric acid according to the following equation?
Hunter-Best [27]

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Explanation:

We have the following chemical reaction:

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if           2 moles of H₃PO₄ are reacting with 3 moles of Zn

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mass of Zn = 0.354 × 65 = 23.01 g

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brainly.com/question/13911775

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