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Margarita [4]
3 years ago
8

Which of the following is an example of acceleration? Select one:

Physics
1 answer:
REY [17]3 years ago
8 0
Acceleration' is any change in the speed or direction of motion. we can look through the choices:
A).  /
B).   No.  Neither speed nor direction changed.
C).  /
D).  Yes.  The boy's direction changed.  

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With which part of the brain is awareness typically associated?
weeeeeb [17]

Answer:cerebral cortex

Explanation:

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Where could convection currents form? Check all that apply.
KatRina [158]
<h3><u>Answer;</u></h3>
  • In a freshwater lake
  • In the atmosphere
  • In Earth's mantle
<h3><u>Explanation</u>;</h3>
  • <em><u>Convection currents are types that cause the process of convection, which the transfer of heat energy that occurs in fluids.</u></em>
  • <em><u>Convection currents are circular patterns that occurs in fluids such that the less dense warm fluids rises up while denser cold fluids sinks, </u></em>it is this movement of less dense warm fluid and denser cold fluids that creates circular patterns that causes the process of convection to take place.
  • <em><u>Convection currents may occur in the atmosphere where warm air rises while cold denser air sinks or moves towards the bottom, it may also occur in the mantle of the Earth and water or water bodies such as lakes.</u></em>
8 0
3 years ago
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How many atoms are in the formula CH4? <br><br> A ) 2 <br><br> B ) 4 <br><br> C ) 5 <br><br> D ) 6
Rufina [12.5K]
B) 4 is the answer for atoms in CH4
6 0
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Help me please forget about you and she was
ra1l [238]

The figure is showing a volume of 2.4 mL becuase it's feel 4 little segments.

Therefore, the answer is 2.4 mL.

5 0
1 year ago
The parallel plates in a capacitor, with a plate area of 7.90 cm2 and an air-filled separation of 2.70 mm, are charged by a 7.90
s2008m [1.1K]

Answer:

A) 26V

Explanation:

(a) the potential difference between the plates

Initial capacitance can be calculated using below expresion

C1= A ε0/ d1

Where d1= distance between = 2.70 mm= 2.70× 10^-3 m

ε0= permittivity of space= 8.85× 10^-12 Fm^-1

A= area of the plate = 7.90 cm2 = 7.90 ×10^-4 m^2

If we substitute the values we

C1= A ε0/ d1

=( 7.90 ×10^-4 × 8.85× 10^-12 )/2.70× 10^-3

C1=2.589 ×10^-12 F= 2.59 pF

Initial charge can be determined using below expresion

q1= C1 × V1

V1=2.589 ×10^-12 F

V1= voltage=7.90 V

If we substitute we have

q1= 2.589 ×10^-12 × 7.90

q1= 20.45×10^-12C

20.45 pC

Final capacitance can be calculated as

C2= A ε0/ d2

d2=8.80 mm= /8.80× 10^-3

7.90 ×10^-4 × 8.85× 10^-12 )/8.80× 10^-3

C1=0.794 ×10^-12 F= 0.794 pF

Final charge= initial charge

q2=q1 (since the battery is disconnected)

q2=q1= 20.45 pC

Final potential difference

V2= q/C2

= 20.45/0.794

= 26V

6 0
3 years ago
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