You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:
So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:
Carbon: 96.08g
Carbon = 49.48%
Nitrogen: 56.028g
Nitrogen = 28.85%
Oxygen: 31.998g
Oxygen = 16.48%
Answer:
In the lab, powdered calcium carbonate reacts much faster with dilute hydrochloric acid than if the same mass was present as lumps of ...
Explanation:
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Answer:
Explanation:
2CH₃(CH₂)₆CH₃ + 25O₂ = 16CO₂ + 18H₂O.
2 moles 25 moles 18 moles
mol weight of octane = 114
72 g of octane = 72 / 114 = .6316 moles
144 g of oxygen = 144 / 32 = 4.5 moles of oxygen.
2 moles of octane reacts with 25 moles of oxygen
.6316 moles of octant will react with 25 x .6316 / 2 moles of oxygen
= 7.895 moles
So oxygen is the limiting reagent
25 moles oxygen produces 18 moles water
4.5 moles of water produces 18 x 4.5 / 25 moles of water
= 3.24 moles of water
= 3.24 x 18 grams of water
= 58.32 grams of water .
The magnitude of the force required to change the length of a spring-like object is directly proportional to the spring constant and the displacement of the spring. Elastic potential energy is directly proportional to the square of the change in length and the spring constant.
Answer: 3 moles
Explanation:
Using the ideal gas equation; PV = nRT
P= Pressure= 2.1 Atm V= Volume = 3.5L T= Temperature = 315K
n= no of moles
R= Gas constant = 0.08206 L .atm. mol-1 . K-1
Making 'n' the subject of the formular, we then have;
n = PV / RT
= 2.1 Atm x 3.5L / 0.08206 L .atm. mol-1 . K-1 x 315K
= 7.35 / 25.849
= 0.28 approx 3moles
