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masha68 [24]
3 years ago
15

Glucose helps maintain life on our planet by storing

Chemistry
1 answer:
hodyreva [135]3 years ago
5 0

Answer:

Chemical energy.

Explanation:

This is biology btw, not chemistry

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Which is a characteristic of atoms?
laila [671]

The  characteristic of atoms is

They are the smallest  units of  matter

<u><em> Explanation</em></u>

Atoms are  the  smallest  constituent  units of matter  and they have  properties of chemical  elements.

Atoms  can not  be broken by any  chemical means.

Atoms of an elements combine together    to form compound.

In  addition atoms  consist nucleus  of positively charged protons, neutral neutrons with  negatively charged electrons.

4 0
3 years ago
Read 2 more answers
If you start with 5 molecules of O2 in the reaction 2Mg+O2--&gt; 2MgO, how much Mg will you need?
joja [24]
You will need 4 molecules of O2.
8 0
3 years ago
How many grams of solid barium sulfate form when 25.0 ml of 0.160 m barium chloride reacts with 68.0 ml of 0.055 m sodium sulfat
GalinKa [24]
Hope this will help you.

8 0
3 years ago
What is the formula for the ionic compound formed between calcium and sulfur?
zheka24 [161]

Answer:

CaS

Explanation:

calcium is Ca2+ and sulfur is S2- because the charges are equal you only need one of  each atom, so the answer is CaS

8 0
3 years ago
A sample of 53.0 of carbon dioxide was obtained by heating 1.31 g of calcium carbont. What is the percent yield for this reactio
MaRussiya [10]

Answer:

92.04%

Explanation:

Given:

Mass of CO₂ obtained = 53.0 grams

Mass of calcium carbonate heated = 1.31 grams

Now,

the molar mass of the calcium carbonate = 100.08 grams

The number of moles heated in the problem = Mass  / Molar mass

= (1.31 grams) / (100.08 grams/moles)

= 0.013088 moles

now,

1 mol of calcium carbonate yields 1 mol of CO₂

thus,

0.013088 moles of calcium carbonate will yield = 0.013088 mol of CO₂

now,

Theoretical mass of 0.013088 moles of CO₂ will be

= Number of moles × Molar mass of CO₂

= 0.013088 × 44 = 0.5758  grams

Thus, the percent yield for this reaction = \frac{\textup{Actual yield}}{\textup{Theoretical yield}}\times100

or

the percent yield for this reaction = \frac{0.53}{0.5758}\times100

or

the percent yield for this reaction = 92.04%

6 0
3 years ago
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