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3 years ago

When a liquid freezes, its particles get . This could result from the pressure .

Chemistry

2 answers:

coldgirl [10]3 years ago

4 0

Answer:

B) closer together, decreasing.

Explanation:

As you heat something, you apply energy to its molecules which tends to move, but here, the opposite happens

leva [86]3 years ago

3 0

Answer: D) closer together; increasing

Explanation:

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What is the color of litmus solution in sodium hydroxide?

Ronch [10]

Answer:

Sodium Hydroxide turns blue litmus red .

4 0

3 years ago

What does the rf value describe on a microscopic level why is this important?

lys-0071 [83]

Answer: The retention factor describes the rate at which a compound migrates on a microscopic level.

The retention factor (Value) serves as a simple measurement of the relative binding of the compound of interest under the experimental conditions.

Retention factor values are used in identification purposes;

• Use to determine the affinity of the solute to the solvent

• Greater retention factor means greater affinity of solute to the solvent

Explanation:

8 0

3 years ago

4. Al2O3 (s) + 6HCl (aq) → 2AlCl3 (aq) + 3H20(1) Find the mass of AlCl3 that is produced when 10.0 grams of Al2O3 react with 10.

slava [35]

Answer:

Are produced 12,1 g of AlCl₃ and 5,33 g of Al₂O₃ are left over

Explanation:

For the reaction:

Al₂O₃ (s) + 6 HCl (aq) → 2AlCl₃ (aq) + 3H₂0(l)

10,0g of Al₂O₃ are:

10,0g ₓ $\frac{1mol}{102g}$ = 0,0980 moles

And 10,0g of HCl are:

10,0 gₓ $\frac{1mol}{36,5g}$ = 0,274 moles

For a total reaction of 0,274 moles of HCl you need:

0,274× $\frac{1molesAl_{2}O_3}{6 mole HCl}$ = 0,0457 moles of Al₂O₃

Thus, limiting reactant is HCl

The grams produced of AlCl₃ are:

0,274 moles HCl × $\frac{2 moles AlCl_{3}}{6 moles HCl}$ × 133 $\frac{g}{mol}$ = 12,1 g of AlCl₃

The moles of Al₂O₃ that don't react are:

0,0980 moles - 0,0457 moles = 0,0523 moles

And its mass is:

0,0523 molesₓ $\frac{102g}{1mol}$ = 5,33 g of Al₂O₃

I hope it helps!

7 0

3 years ago

An ideal gas is brought through an isothermal compression process. The 3.00 mol of gas goes from an initial volume of 261.6×10−6

Eduardwww [97]

Answer : The temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

Explanation : Given,

Initial volume of gas = $261.6\times 10^{-6}m^3$

Final volume of the gas = $138.2\times 10^{-6}m^3$

Heat released = -9340 J

First we have to calculate the temperature of the gas.

According to the question, this is the case of isothermal reversible compression of gas.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

$q=-w$

Thus, w = -q = 9340 J

The expression used for work done will be,

$w=nRT\ln (\frac{V_2}{V_1})$

where,

w = work done = 9340 J

n = number of moles of gas = 3 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = ?

$V_1$ = initial volume of gas

$V_2$ = final volume of gas

Now put all the given values in the above formula, we get the temperature of the gas.

$9340J=3mole\times 8.314J/moleK\times T\times \ln (\frac{261.6\times 10^{-6}m^3}{138.2\times 10^{-6}m^3})$

$T=586.83K$

Now we have to calculate the final pressure of the gas by using ideal gas equation.

$PV=nRT$

where,

P = final pressure of gas = ?

V = final volume of gas = $138.2\times 10^{-6}m^3=138.2\times 10^{-9}L$

T = temperature of gas = 586.83 K

n = number of moles of gas = 3 mole

R = gas constant = 0.0821 L.atm/mole.K

Now put all the given values in the ideal gas equation, we get:

$P\times (138.2\times 10^{-9}L)=3mole\times (0.0821L.atm/mole.K)\times (586.83K)$

$P=1.046\times 10^{9}atm$

Therefore, the temperature and the final pressure of the gas is, 586.83 K and $1.046\times 10^{9}atm$ respectively.

6 0

3 years ago

5.04 Discussion: Reaction-Rate Factors

saul85 [17]

Increasing the surface area of the reactant by pelletizing the calcium carbonate, and increasing the concentration of hydrochloric acid resulted in increase in the rate of reaction.

<h3>What is reaction rate?</h3>

Reaction rate refers to the rate at which reactant molecules are consumed or the rate at which product molecules are formed.

The factors that affect reaction rate include:

Temperature
Concentration
Surface area of reactants
Nature of reactants
Presence of catalysts

Given an experiment to determine effect of surface area of reactants and concentration on reaction rate of dilute hydrochloric acid and calcium carbonate:

It was observed that increasing the surface area of the reactant by pelletizing the calcium carbonate and increasing the concentration of hydrochloric acid made the reaction proceed faster.

In conclusion, reaction rate increases with increase in surface area.

Learn more about factors affecting reaction rate at: brainly.com/question/14817541

#SPJ1

8 0

2 years ago

When a liquid freezes, its particles get ____. This could result from the pressure ____.

When a liquid freezes, its particles get . This could result from the pressure .