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musickatia [10]
3 years ago
7

How many grams are in 2.3 x 10-4 moles of calcium phosphate, Ca3(PO3)2?

Chemistry
1 answer:
scZoUnD [109]3 years ago
5 0

Answer:

7136900g or 7136 kg

 

Explanation:

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At STP how many moles or helium would occupy a volume of 12 liters?
butalik [34]
1 mole ------------- 22.4 L ( at STP )
?? mole ---------- 12 L

12 x 1 / 22.4 => 0.5357 moles

hope this helps! 
5 0
4 years ago
What is the pH of a 0.40 M solution of C6H5COOH?
melomori [17]
What are the answer choices?
4 0
3 years ago
The Concentration of C6H12O6 May be represented as?
Amiraneli [1.4K]

Answer:

A 12 oz Coca Cola contains 39g of sugar or C6H12O6. 

To calculate for the molarity of sugar in the soda, convert 39 grams of sugar to moles sugar:

39g/ 180.16 g/mol = 0.216 mol sugar

then, convert 12 oz to L:

12oz / (1oz/0.02957L) = 0.35484 L

therefore the concentration of sugar in the soda is:

M = mol sugar / L sol'n

   = 0.216 mol sugar / 0.35484 L

   = 0.609 M

Explanation:

6 0
3 years ago
Read 2 more answers
Which of the following shows how rate depends on concentrations of reactants?
Katarina [22]

Answer:

Rate = k(A)m(B)n

Explanation:

A.P.E.X.

6 0
3 years ago
Enter your answer in the provided box.
Lina20 [59]

Answer:

5.06atm

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 1.34 atm

P2 = ?

V1 = 5.48 L

V2 = 1.32 L

T1 = 61 °C = 61 + 273 = 334K

T2 = 31 °C = 31 + 273 = 304K

Using P1V1/T1 = P2V2/T2

1.34 × 5.48/334 = P2 × 1.32/304

7.34/334 = 1.32P2/304

Cross multiply

334 × 1.32P2 = 304 × 7.34

440.88P2 = 2231.36

P2 = 2231.36/440.88

P2 = 5.06

The final pressure is 5.06atm

6 0
3 years ago
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