The correct answer is option D. That is, the branch of Physics that study the particles movement at any speed, including very high speeds is Relativity
<h3>
Difference between Kinematic and Dynamics </h3>
Kinematic is a branch of Physics that deal with a study of particle's motion without considering the cause of the motion. While dynamics deals with the motion of a particle as well as the causes of the motion.
The branch of Physics that study the particles movement at any speed,
including very high speeds is Relativity.
We have relativity of mass, relativity of time and relativity of length. All deal with the speed of light which is the fastest speed on earth as of now.
Therefore, the correct answer is option D. That is, the branch of Physics that study the particles movement at any speed, including very high speeds is Relativity.
Learn more about Relativity here: brainly.com/question/364776?source=aidnull
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E, 63% of the value. I forget the rationale behind it but I learnt that in engineering. 90% confident for that answer.
They are helium nuclei, which consist of two protons and two neutrons. The net spin on an alpha particle is zero. They result from large, perilous atoms via a process called alpha decay.
<h3>What is
helium nuclei?</h3>
- The nucleus of the helium atom also understood as the α-particle, includes two protons and two neutrons, encompassed by two electrons.
- Alpha particles are helium nuclei with two protons and two neutrons attached. The development of their high mass and an electrical charge is their inability to infiltrate as deep as other particles such as protons and electrons.
- Particle beams contain α (alpha)-particles, β (beta)-particles, neutron beams, etc. α-particles are helium middles consisting of two protons and two neutrons that have lived removed at high speed, while β-particles are electrons removed from a nucleus. Particle shafts also include neutron beams and proton beams.
To learn more about helium nuclei, refer to:
brainly.com/question/26226232
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Answer:
While falling, the magnitude of the acceleration of the egg is 9.82 m/s²
While stopping, the magnitude of the deceleration of the egg is 79.3 m/s²
Explanation:
Hi there!
The equation of velocity of the falling egg is the following:
v = v0 + a · t
Where:
v = velocity at time t.
v0 = initial velocity.
a = acceleration.
t = time
Let´s calculate the acceleration of the egg while falling. Notice that the result should be the acceleration of gravity, ≅ 9.8 m/s².
v = v0 + a · t
11.1 m/s = 0 m/s + a · 1.13 s (since the egg is dropped, the initial velocity is zero). Solving for "a":
11.1 m/s / 1.13 s = a
a = 9.82 m/s²
While falling, the magnitude of the acceleration of the egg is 9.82 m/s²
Now, using the same equation, let´s find the acceleration of the egg while stopping. We know that at t = 0.140 s after touching the ground, the velocity of the egg is zero. We also know that the velocity of the egg before hiiting the ground is 11.1 m/s, then, v0 = 11.1 m/s:
v = v0 + a · t
0 = 11.1 m/s + a · 0.140 s
-11.1 m/s / 0.140 s = a
a = -79.3 m/s²
While stopping, the magnitude of the deceleration of the egg is 79.3 m/s²