Question

What is the equation of the line that passes through the point (-6, -6) and has a slope of -1/3?

Answer 1

Answer:

Step-by-step explanation:

Let's find an equation by starting with the slope intercept form:

y = mx + b

where m is the slope and b the y-intercept (the value of y when x=0).

We are given the slope, so:

y = -(1/3)x + b

Now we need to find a value for b that will force the line to go through point (-6,-6).  We can determine by putting the point (-6,-6) into the equation and solving for b:

y = -(1/3)x + b

-6 = -(1/3)(-6) + b   [Enter the point (-6,-6]

-6 = 2 + b

b = - 8

The equation becomes y = -(1/3)x - 8.

See the attachment.