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1 year ago

Choose all the statements that are true for Relative Age Dating.

Chemistry

1 answer:

Lorico [155]1 year ago

3 0

Answer:

Which one goes in the absolute dating column, relative column, and both.

Lesson 4.07: Relative and Absolute Dating DIRECTIONS: Use the facts below to complete the chart for Relative and Absolute Dating.

1. The Law of Superposition – the age of an object may be determined by the depth at which it is found, the deeper the object is in the Earth, the older it is.

2. Gives scientist an exact age of a rock fossil.

3. Scientist use their knowledge of the half-life of carbon and uranium isotopes to measure the age of the rock or fossil .

4. Used to determine the age of an object, when there is no record of a living thing.

5. Gives the approximate age of a fossil or artifact.

6. Used by scientist to determine the age of a fossil or artifact.

7. Estimates the order of geological or prehistoric events, but cannot be used to determine when these events have occurred.

8. Measures the decay of a rock or fossil to measure the age.

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The picture shows two containers filled with a gas.

aniked [119]

Answer: The average kinetic energy of the gas particles is greater in container B because it has a higher temperature.

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1 year ago

What are some advantages and disadvantages to the acid rain management techniques?

mr_godi [17]

Disadvantages of acid rain:
• Acid rain affects the fresh water ponds and lakes and destroys the aquatic life as some species of fishes are rare and may be extinct
• it can affect the trees particularly those that are high altitude
• It can damage historical monuments and buildings
•soil can be affected and can lead to deaths of good microbes

Advantages of acid rain:
• it makes holes in limestone below ground, which creates caves and places to store groundwater, as well as providing habitat for some species
• But the new study shows that sulfuric in acid may have benefits, limiting global warming by counteracting the natural production of methane gases by microbes in wetland areas.

Of course you should do more studying on acid rain but these are the simple ones

5 0

2 years ago

Read 2 more answers

Select the correct answer. Elements Electronegativity aluminum (Al) 1.61 calcium (Ca) 1 carbon (C) 2.55 chlorine (Cl) 3.16 fluor

marishachu [46]

Answer: Fe - O

Explanation:

1) Start by showing the chart information in a more understandable way:

Elements ---------- Electronegativity

aluminum (Al) ----- 1.61

calcium (Ca) ------- 1

carbon (C) ---------- 2.55

chlorine (Cl) -------- 3.16

fluorine (F) --------- 4

hydrogen (H) ------ 2.2

iron (Fe) ------------- 1.83

nitrogen (N) --------- 3.04

oxygen (O) ----------- 3.44

phosphorus (P) ----- 2.19

potassium (K) -------- 0.82

silicon (Si) ------------- 1.9

sulfur (S) --------------- 2.58

2) Find the electronegativity differences for the atoms in each compound:

i) Ca – Cl: 3.16 - 1 = 2.16

ii) Fe – O: 3.44 - 1.83 = 1.61

iii) H – S: 2.58 - 2.2 = 0.38

iii= F – F = 4 - 4 = 0

3) Analysis

i) The higher the electronegativity difference between two non-metal elements, the the more the polar the covalent bond. Therefore, the bond H - S is the most polar among the non-metal - non-metal bonds listed. But 0.38 is a small difference, so this is not very polar.

ii) For metal - non-metal bonds, when the difference in electronegativities is too high (close to or greater than 2.0) the ionic character is dominant, and so you cannot classify the bond as polar but as ionic. Therefore, Ca - Cl with 2.16 electronegativity difference is a ionic bond.

iii) The bond in Fe – O has electronegativty difference of 1.61, so it is yet covalent, and highly polar.

Read more on Brainly.com - brainly.com/question/1309389#readmore

8 0

2 years ago

Read 2 more answers

How many miles are in 215 grams of water

Irina18 [472]

You're off to a good start, now find the mass of H2O and put it under I mol,

then multiply 1 mol over the mass of H2O by 215 grams

3 0

3 years ago

At its critical point, ammonia has a density of 0.235 g cm23. You have a special thickwalled glass tube that has a 10.0mm outs

salantis [7]

Answer:

$\large \boxed{\text{69.3 mg}}$

Explanation:

1. Volume of sealed tube

Assume the sealed tube is a right circular cylinder in which the cap and the base are also 4.20 mm thick.

Its outside dimensions are 155 mm long × 10.0 mm diameter.

Its inside dimensions are

h = 155 mm - 2 × 4.20 mm = 146.6 mm

r = 5.0 mm - 4.20 mm = 0.8 mm

V = πr²h = π(0.8)²× 146.6 mm³ = 294.8 mm³ = 0.2948 cm³

2. Calculate the mass of NH₃

$\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho & = &\dfrac{m}{V}\\\\0.235 \text{ g$\cdot$ cm}^{-3} & = & \dfrac{m}{\text{0.2948 cm}^{3}}\\\\m & = & \text{0.0693 g}\\& = & \textbf{69.3 mg}\\\end{array}\\\text{You must seal $\large \boxed{\textbf{69.3 mg}}$ of ammonia in the tube.}$

4 0

3 years ago