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kirill115 [55]
3 years ago
7

When conducting an experiment which is the best way to record data

Chemistry
1 answer:
kolezko [41]3 years ago
8 0
To go back on the text and get your answer also if u are not in this grade in 4th and 5th grade they taught race so just use that trace stands for
R-restate your answer
A-answer al parts of your question
C-Cite your evidence
And
E-extend and or explain hope this helps
You might be interested in
If the aluminum block is initially at 25 ∘C∘C, what is the final temperature of the block after the evaporation of the alcohol?
Effectus [21]

Answer:

Final temperature of aluminum block = 12.1°C

<em>Note: The question is not complete. The complete question is given below:</em>

<em>If the aluminum block is initially at 25 ∘C, what is the final temperature of the block after the evaporation of the alcohol? Assume that the heat required for the vaporization of the alcohol comes only from the aluminum block and that the alcohol vaporizes at 25 ∘C. Heat of vaporization of the alcohol at 25 ∘C is 45.4 kJ/mol Suppose that 1.12 g of rubbing alcohol (C3H8O) evaporates from a 73.0 g aluminum block.</em>

Explanation:

Heat lost by aluminum block = heat required for vaporization of alcohol

Heat required to vaporize ethanol, H = mass of alcohol * heat of vaporization of alcohol

Mass of alcohol = 1.12 g; molar mass of rubbing alcohol = 60 g/mol

Heat of vaporization = (45.4 kJ/mol)/ 60 g/mol =  0.75666 kJ/g

H = 1.12 g × 0.7566 kJ/g

H = 0.8474 kJ = 847.4 J

Heat lost by aluminum block, Q = -(mass × specific heat capacity × temperature change)

Mass of aluminum block = 73.0 g

Specific heat capacity of aluminum = 0.900 J/g

Temperature change = (Final temperature, T - 25)

Q = -73.0 g × 0.900 J/g × (T - 25)

Q = -65.7 J × (T - 25°C)

Since, Heat lost by aluminum block = heat for vaporization of alcohol

-65.7 J × (T - 25°C) = 847.4 J

T - 25 = 847.4/-65.7

T - 25 = -12.9

T = -12.9 + 25

T = 12.1°C

5 0
3 years ago
Wich is not a characteristic common to all minerals
ahrayia [7]

Metallic luster is not a characteristic common to all minerals.

7 0
4 years ago
gamma rays have an approximate wavelength of 1.0x10^-13 meters. what is the approximate energy of a gamma-ray?
Bogdan [553]

Answer:

E = 19.89 × 10⁻¹³ J

Explanation:

Given data:

Wavelength of gamma ray= 1.0× 10⁻¹³ m

Energy of gamma ray = ?

Solution:

Formula:

E = h c/λ

h = plancks constant  = 6.63× 10⁻³⁴ js

c = speed of light = 3 ×10⁸ m/s

by putting values,

E = 6.63× 10⁻³⁴ js × 3 ×10⁸ m/s /1.0× 10⁻¹³ m

E = 19.89 × 10⁻²⁶ J.m/ 1.0× 10⁻¹³ m

E = 19.89 × 10⁻¹³ J

8 0
3 years ago
can someone help me with these? I just started chemistry this semester, and since it's involving math I don't see myself doing g
V125BC [204]

Any non zero digits are significant. (120 has 2 sig figs)

Zeroes between significant digits are significant. (103 has 3 sig figs)

Zeroes only count if there is a decimal point and if they are following a significant digit. (.600 has 3 sig figs; .067 has 2 sig figs)

1) <u>1278.50</u> = 6 sig figs

2) <u>12</u>0000 = 2 sig figs

3) <u>90027.00</u> = 7 sig figs

4) 0.00<u>53567</u> = 5 sig figs

5) <u>67</u>0 = 2 sig figs

6) 0.00<u>730</u> = 3 sig figs

That's all I'm gonna do so yeah.

Now for the rounding, it's basically rounding but it must have the x amount of sig figs after rounding. It's pretty hard to explain.

19, I'm not really sure. Might be 120 with a decimal point at the end.

20) 5.457, alright so here, since we are rounding to three significant digits, we look at the third sig fig. The third sig fig here would be 5. Then we just round. Since the number next to 5 is 7, we round 5 up to 6.

So 5.457 rounded to 3 sig figs would be 5.46

21) 0.0008769, the third sig fig here would be 6. You round 6 up to 7 because the number next to it is 9.

So 0.0008769 rounded to 3 sig figs would be 0.000877

So I hope you get it, I'm gonna let you do the rest.

4 0
2 years ago
In your own words, explain what the concept of density means—without using the formula.
vladimir1956 [14]

Answer:

The amount of mass in a certain volume

Explanation:

4 0
3 years ago
Read 2 more answers
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