The periods of oscillation for the mass–spring systems from largest to smallest is:
- m = 4 kg , k = 2 N/m (T = 8.89 s)
- m = 2 kg , k = 2 N/m (T = 6.28 s)
- m = 2 kg , k = 4 N/m (T = 4.44 s)
- m = 1 kg , k = 4 N/m (T = 3.14 s)
<h3>Explanation:</h3>
The period of oscillation in a simple harmonic motion is defined as the following formulation:

Where:
T = period of oscillation
m = inertia mass of the oscillating body
k = spring constant
m = 2 kg , k = 2 N/m


T = 6.28 s
m = 2 kg , k = 4 N/m


T = 4.44 s
m = 4 kg , k = 2 N/m


T = 8.89 s
m = 1 kg , k = 4 N/m


T = 3.14 s
Therefore the rank the periods of oscillation for the mass–spring systems from largest to smallest is:
- m = 4 kg , k = 2 N/m (T = 8.89 s)
- m = 2 kg , k = 2 N/m (T = 6.28 s)
- m = 2 kg , k = 4 N/m (T = 4.44 s)
- m = 1 kg , k = 4 N/m (T = 3.14 s)
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The formula for half-life is:

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope. Let's plug in our values to the equation:

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.
What do you mean? What step of weathering? They help process dead organisms, and transfer soil.
Answer:
d = <23, 33, 0> m
, F_W = <0, -9.8, 0>
, W = -323.4 J
Explanation:
We can solve this exercise using projectile launch ratios, for the x-axis the displacement is
x = vox t
Y Axis
y =
t - ½ g t²
It's displacement is
d = x i ^ + y j ^ + z k ^
Substituting
d = (23 i ^ + 33 j ^ + 0) m
Using your notation
d = <23, 33, 0> m
The force of gravity is the weight of the body
W = m g
W = 1 9.8 = 9.8 N
In vector notation, in general the upward direction is positive
W = (0 i ^ - 9.8 j ^ + 0K ^) N
W = <0, -9.8, 0>
Work is defined
W = F. dy
W = F dy cos θ
In this case the force of gravity points downwards and the displacement points upwards, so the angle between the two is 180º
Cos 180 = -1
W = -F y
W = - 9.8 (33-0)
W = -323.4 J
<span>The three main types of stress in a rock are shearing, tension, and compression. hope. that helped</span>