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I am Lyosha [343]
3 years ago
12

A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is

0.19 m below the level of the water that is in the tank. If the top of the trough is open to the atmosphere, what is the speed of the water as it leaves the hole? Assume that the trough is large enough that the velocity of the water at the top is zero. The acceleration of gravity is 9.81 m/s 2 . Answer in units of m/s.
Physics
1 answer:
Crazy boy [7]3 years ago
5 0

Answer:

v=1.93m/s

Explanation:

From the concept of fluids mechanics we know that if a tank has a hole at the bottom, the equation that we need to use is:

v=\sqrt{2gh}

Since we know gravity and its hight

v=\sqrt{2*(9.81m/s^{2})(0.19m) }=1.93m/s

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A spring suspended vertically is 11.9 cm long. When you suspend a 37 g weight from the spring, at rest, the spring is 21.5 cm lo
Naddika [18.5K]

Answer:

Time period of oscillations is 0.62 s

Explanation:

Due to suspension of weight the change in the length of the spring is given as

\Delta L = L_f - L_i

\Delta L = 21.5 - 11.9 = 9.6 cm

now we know that spring is stretched due to its weight so at equilibrium the force due to weight is counter balanced by the spring force

mg = kx

0.037 (9.81) = k(0.096)

k = 3.78 N/m

Now the period of oscillation of spring is given as

T = 2\pi \sqrt{\frac{m}{k}}

Now plug in all values in it

T = 2\pi \sqrt{\frac{0.037}{3.78}}

T = 0.62 s

5 0
3 years ago
PLEASE HELP ME!!!!! You draw an arrow from left to right on a piece of paper and place the paper well behind a glass of water. Y
julia-pushkina [17]

Answer:

I think it is the first one: <u>The arrow appears reversed because light is bent as it enters the water, and again as it exits. The two light paths cross, making the direction of the arrow appear crossed.</u>

Explanation:

7 0
2 years ago
A baseball is moving at a speed of 2.2m/s when it strikes the catchers glove. The paddding of the glove is compressed by 24mm be
Andre45 [30]

Average acceleration of the baseball: -101 m/s^2

Explanation:

Since the motion of the baseball is a uniformly accelerated motion, we can use the following suvat equation:

v^2-u^2=2as

where

u is the initial velocity

v is the final velocity

a is the acceleration

s is the displacement of the object

For the baseball in this problem, we have:

u = 2.2 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

s = 24 mm = 0.024 m is the displacement of the ball while decelerating

Therefore, we can solve for a to find the acceleration:

a=\frac{v^2-u^2}{2s}=\frac{0-2.2^2}{2(0.024)}=-101 m/s^2

where the negative sign means the baseball is slowing down.

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

4 0
3 years ago
A time-varying horizontal force F(t) = At4 + Bt2 acts for 0.500 s on a 12.25-kg object, starting attime t = 1.00 s. In the SI sy
PSYCHO15rus [73]

Answer:

3.82 Ns

Explanation:

Time varying horizontal Force is given as

F(t) = A t⁴ + B t²

F(t) = 4.50 t⁴ + 8.75 t²

Impulse imparted is given as

I = \int_{0}^{t}Fdt

I = \int_{0}^{1}Fdt

I = \int_{0}^{1}(4.50 t^{4} + 8.75 t^{2})dt

I = ((0.9) (1)^{5} + (2.92) (1)^{3})

I = 3.82 N-s

7 0
3 years ago
Read 2 more answers
The loudness l of a sound, measured in decibels, is given by l=10log10r, where r is the sound's relative intensity. suppose one
marishachu [46]

Answer

given,                              

I is the loudness of sound

I = 10 Log₁₀ r                  

r is relative intensity                    

at when relative intensity is 10⁶        

I = 60 dB                                                  

how much louder when 100 people would be talking together

I = 10 Log₁₀ r                

I = 10 Log₁₀ (10⁶ x 100)  

I = 10 Log₁₀ (10⁸)                

I = 80 dB                      

hence, the intensity will be increased by (80 dB -60 dB) 20 dB when 100 people start talking together.

5 0
4 years ago
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