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Andrew [12]
3 years ago
5

What does it mean to say that the average speed of a car is 35 miles per hour?

Physics
1 answer:
LenKa [72]3 years ago
6 0
It means that the car has covered

(35 miles) x (the number of hours since it started traveling).

At some points during that time, the car was most likely moving
faster or slower than 35 miles per hour.  We don't know.  We only
know that it covered  (35 miles) x (the number of hours since it left).
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Calculate the total energy of 2.0 kg object moving horizontally at 10 m/s 50 meters above the surface
mina [271]
We have:

Total Energy: KE + GPE
KE (Kinetic Energy) = \frac{1}{2} m*v^2
GPE (Gravitational Potential Energy) = m*g*h

Data:
m (mass) = 2.0 Kg
v (speed) = 10 m/s
h (height) = 50 m
Use: g (gravity) = 10 m/s²

Formula:

Total Energy: KE + GPE
TE =  \frac{1}{2} m*v^2 + m*g*h

Solving:
TE = \frac{1}{2} m*v^2 + m*g*h
TE = \frac{1}{2} *2.0*10^2 + 2.0*10*50
TE =  \frac{2.0*100}{2} + 1000
TE =  \frac{200}{2} + 1000
TE = 100 + 1000
\boxed{\boxed{TE = 1100\:Joule}}\end{array}}\qquad\quad\checkmark


5 0
2 years ago
Read 2 more answers
A runner with a mass of 80kg accelerates from 0 to 9 m/s in 3 s find the net force
frosja888 [35]
So, first you find your acceleration which is 3m/s^2, using the acceleration formula.
Now set up your equation, F=ma, so put in the stuff, F=80kg·3m/s^2. Then solve your equation by multiplying, and you get F=240N, since newtons are your measurement.
Hope this helps
4 0
3 years ago
Is 5g greater than 20.43 mg
worty [1.4K]

yes that's true 6g is larger

4 0
3 years ago
Read 2 more answers
A projectile is fired with a velocity of 22 m/s at an angle of 25°. What is the vertical component of the velocity?
7nadin3 [17]

Answer:

Vertical component of velocity is 9.29 m/s

Explanation:

Given that,

Velocity of projection of a projectile, v = 22 m/s

It is fired at an angle of 22°

The horizontal component of velocity is v cosθ

The vertical component of velocity is v sinθ

So, vertical component is given by :

v_y=v\ sin(25)

v_y=22\ m/s\times\ sin(25)

v_y=9.29\ m/s

Hence, the vertical component of the velocity is 9.29 m/s

3 0
3 years ago
How to derive the fourth equation of motion?
Leya [2.2K]

Answer:

To derive the fourth equation of motion, first we have to consider the equation for acceleration and then to rearrange it. or v2 = u2 + 2as and this equation of motion can be used to find the final velocity or the distance travelled if the other values are given.

Explanation:

v= u + at

s =( u + v ) t /2

s = ut + at2/2

v2 = u2 + 2as

6 0
2 years ago
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