Answer:
Island arc
Explanation:
When two oceanic plates share a convergent type of plate boundary, the denser oceanic plate will subduct below the less dense oceanic plate. This will result in the formation of the subduction zone, where the rocks are being pulled down to the mantle. This subduction zone is typically marked by the presence of a narrow depression commonly known as an oceanic trench, that lies just above the zone.
The rocks of the subducting plate undergo partial melting and mix up with the magma that rises upwards towards the surface due to the force exerted by the convection currents. This later gives rise to the formation of volcanoes or a chain of volcanoes which are commonly known as an island arc.
Today we can make observations that would lead us to the same conclusion as newton. If you throw a baseball in the air, it always comes back down. This is because of gravity. duh.
Explanation:
Given that,
Radius of the disk, r = 0.25 m
Mass, m = 45.2 kg
Length of the ramp, l = 5.4 m
Angle made by the ramp with horizontal, 
Solution,
As the disk starts from rest from the top of the ramp, the potential energy is equal to the sum of translational kinetic energy and the rotational kinetic energy or by using the law of conservation of energy as :
(a) 
h is the height of the ramp


v is the speed of the disk's center
I is the moment of inertia of the disk,






v = 4.52 m/s
(b) At the bottom of the ramp, the angular speed of the disk is given by :



Hence, this is the required solution.