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stepan [7]
2 years ago
11

I need help plz thanks

Mathematics
1 answer:
m_a_m_a [10]2 years ago
4 0
What are the answer choices in the drop down?
You might be interested in
Use substitution to solve the system of equations.
kakasveta [241]

Answer:

C (let me know if I am wrong!)

Step-by-step explanation:

We need to solve the equation.

If 5x+y = -24, then -24 - 5x = y.

x+ 3(-24-5x) = -2

= -14x-72=-2

= -14x-72+72=-2+72

= -14x=70

= -5

If x = -5, then -5 + 3y = -2.

3y = -2+5

3y = 3

y=1

So the answer is C.

4 0
3 years ago
Can someone help me with these problems
galina1969 [7]

Answer:

a.2

b.2

c.3x

a.3(x+2)

b.-(2-x)

c.3x-2

4 0
3 years ago
Read 2 more answers
A point has no physical characteristics.<br><br> True<br> False
Burka [1]
Thank you for posting your question here at brainly. Feel free to ask more questions.  

<span>The best and most correct answer among the choices provided by the question is TRUE.</span><span>      
    </span><span>
<span>Hope my answer would be a great help for you.</span></span>
5 0
3 years ago
Convert each percentage into a decimal and match them with the appropriate result.
skad [1K]

Answer:

32% = 0.32

50% = 0.50

34% = 0.34

Step-by-step explanation:

0.32 = 32%

0.50 = 50%

0.34 = 34%

P.S Can I have brainliest?

5 0
2 years ago
Read 2 more answers
Hey Mahfia, please help! Find an equation in standard form for the hyperbola with vertices at (0, ±10) and asymptotes at
Dafna1 [17]

Answer:

\huge\boxed{  \red{ \boxed{ \tt{ \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1}}}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • conic sections
  • PEMDAS
<h3>tips and formulas:</h3>
  • \sf hyperbola \:equation :  \\  \sf  \frac{ {x}^{2} }{ {a}^{2} }   -  \frac{ {y}^{2} }{ {b}^{2} }  = 1
  • vertices of hyperbola:(±a,0) and (0,±b) if reversed
  • \sf \: asymptotes :  \\ y =   \pm\frac{b}{a} x
<h3>given:</h3>
  • vertices: (0,±10)
  • the hyperbola equation is inversed since the vertices is (0,±10)
  • asymptotes:\pm \frac{5}{6}x
<h3>let's solve:</h3>
  • the asymptotes are in simplest and we know b is ±10

according to the question

  1. y =  \sf  \frac{5 \times 2}{6 \times 2} x \\ y =  \frac{10}{12} x

therefore we got

  • a=12
  • b=10

note: the equation will be inversed

let's create the equation:

  1. \sf substitute \: the \: value \: of \: a \: and \: b :  \\  \sf  \frac{ {y}^{2} }{ {10}^{2} }  -  \frac{ {x}^{2} }{ {12}^{2} }  = 1

3 0
3 years ago
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