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3 years ago

Based on these answers how can I determine when electric field strength is affected or not

Physics

1 answer:

Stolb23 [73]3 years ago

6 0

It's not that hard. Let me explain...

There are two ways to remember this.

The first one is by using the formula for the electric strength (E)

E = k × (Q / r^2) , where:

k is a constant
Q is the "central" charge. The one producing the electric field. <u>Not</u> the one we use to test it.
r is the distance between the charges

As you can see, field's strength is proportional to the magnitude of Q, and inverse proportional to the square of the distance. The field does not care how much you alter the charge you positioned in ot to test it.

Although that is the only way to work out the problem, there are many ways to remember it. Given that i have difficulty in remembering formulas, i always try to derive it from something i know.

By definition: E is equal to the force acted on the test charge, divided by its value.

E = F / q

F --> Coulomb's force
q --> test charge

Since i remember that:

F = k ( Q × q) / r^2

just take out from the expression the q term, since you divided by it, and all it remains is the strength of the field.

In other words, the strength changes as long as something from the expression is altered.

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An interglacial is a period of time that occurs between Ice Ages. It’s marked by warmer temperatures and milder climates. During

Korolek [52]

Answer:

The correct answer is - 43%.

Explanation: The increase in CO2 between these two suggested periods is approximately 43%. Even though it is a natural process that the CO2 levels vary in the atmosphere, still this is not the same case nowadays. Nowadays, or rather in the past few decades, apart from the natural increase of CO2 in the atmosphere, it has seen a much more increased levels because of the human activity. The industrial facilities and the vehicles, the cutting of the forests and burning the wood (there's both release of CO2 from the burning of the trees and loss of natural accumulator of the CO2), are just some of the more important human activities that contribute to a significant rise in the CO2 levels.

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3 years ago

A 60 kg boy and 40 kg girl stand on skateboards on a frictionless horizontal surface. The boy pushes the girl away from him. The

bezimeni [28]

Here in the above situation when boy pushes the girl there will be equal and opposite force on boy as per Newton's III law.

Due to this action reaction law boy will also go back with some speed.

Since there is no external force on this girl + boy system so we can use momentum conservation principle here.

As per momentum conservation

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

$60*0 + 40*0 = 60*v_{1f} + 40*0.3$

$0 = 60*v_{1f}+ 12$

$v_{1f} = -0.2 m/s$

So boy will go back with speed 0.2 m/s

Part b)

Since the boy and girl will always exert same force on each other by Newton's III law so it has no it matter whether the boy pushed the girl, the girl pushed the boy, or they put their hands together and pushed each other away.

As in all above cases the as per Newton's III law the force on them is always equal and opposite.

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3 years ago

how high will the hill be if a marble is dropped 120cm? This is based off the roller coaster lab using foam pipes without using

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3 years ago

A mountain 10.0 km from a person exerts a gravitational force on him equal to 2.00% of his weight. (a) Calculate the mass of the

LiRa [457]

Answer:

a) M = 2,939 10¹⁷ kg , b) $M_{e}$ / M = 2 10⁷

Explanation:

a) The equation for gravitational force is

F = G m M / r²

Where G is the gravitational constant that is worth 6.67 10⁻¹¹ N m² / kg², m the mass epa person. M the mass of the Mountain and r the distance between them.

The value of this force is 2% of the person's weight

F = 0.02 W = 0.02 mg

we replace

0.02 mg = G m M / r²

M = 0.02 g r² / G

r = 10 km = 10 10³ m = 1.0 10⁴ m

M = 0.02 9.8 (10⁴)² / 6.67 10⁻¹¹

M = 2,939 10¹⁷ kg

b) to compare the masses we find their relationship

$M_{e}$ / M = 5.98 1024 / 2,939 1017

$M_{e}$ / M = 2 10⁷

c) treating the mountain as a point object

d) The mountain is not spherical so the distance changes depending on the height of the mountain

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3 years ago

How do mixtures differ from compounds?

julsineya [31]

A compound is a combination of molecules. Molecules and formula units are made of two or more different types of atoms either ionically or covalently bonded.
Compounds are made with chemical bonds. can only separated by a chemical ways.

Mixtures are two or more types of elements that are NOT chemically bonded. and we can separated by a physical ways.

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3 years ago