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crimeas [40]
3 years ago
8

How can you tell if a chemical reaction has occurred?

Chemistry
1 answer:
qwelly [4]3 years ago
7 0
Gas formation, precipitate formation, color change, temperature change, or odor 
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Answer:

applying for a license

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The use of microorganism in our day to day life is.................
Ipatiy [6.2K]

Explanation:

The use of microorganism in our day to day life is making medicine.

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Which of the following is the correct wedge and dash conformation for the following Newman projection?
kakasveta [241]

We have that  the correct wedge and dash conformation for the following Newman projection is

IV

From the Diagrams above

Two CH_3 groups points on opposite sides in plane

Two Br are on same side  of plane

Two H also on same side of the plane so the plausible  structure is IV

Therefore

The Correct option is IV

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8 0
3 years ago
What is more soluble, ammonium chloride or sodium chloride?
vodka [1.7K]

Answer:

Explanation:

When Ammonium Chloride is heated at high temperature, it sublimes and gives rise to white colored dense fumes. ... But, Sodium Chloride does not give rise to any white colored fumes upon heating.

8 0
3 years ago
Five students performed a Kjeldahl nitrogen analysis of a protein sample. The following weight % nitrogen values were determined
Sunny_sXe [5.5K]

Answer:

G_calculated = 1.756

The outlier should be rejected, as G_cal > G_tab (= 1.463) at 95 % confidence.

Explanation:

The Grubb's test is used for identifying an outlier in data, which is from the same population. For this, a statistical term, G, is calculated for the suspected outlier. If the calculated value is greater than the tabulated G value then the suspected value is rejected. This term is given as,

G_calculated = | suspect value - mean| / s

Here,  suspect value is 13.8, mean is to be taken of all the data (including suspected value). s is the standard deviation of the sample data.

s is calculated from the following formula:

s = (Σ(xi - x)²/(N-1))^1/2

Here, x is the mean, which is 15.24, xi is individual value and N is the total number of data (5).

From the above formula, s is found to be

Standard Deviation, s = 0.820

Now for G value,

G_calculated = | 13.8 - 15.24| / (0.820)

G_ calculated = 1.756

The tabulated G value at 95 % confidence and N -1 (5 - 1 = 4) degree of freedom is, 1.463.

As calculated G (1.756) is greater than the tabulated G (1.463), the value 13.8 is considered an outlier at 95 % confidence.  

3 0
3 years ago
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