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Naddika [18.5K]
3 years ago
9

A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered

to the string is quadrupled, by what factor does the amplitude change? 16
Physics
1 answer:
just olya [345]3 years ago
5 0

Answer:

Amplitude changes by factor of 2 means double.

Explanation:

Given:

If the power delivered to the string is quadrupled.

From the formula of power transmitted by a sinusoidal wave on a stretched string is,

  P = \frac{1}{2} \mu  \omega ^{2} A^{2}   v

Where \mu = mass per unit length, \omega  = angular speed, A = amplitude, v = wave speed, P = power delivered.

Here we need only two terms power and amplitude.

       P∝ A^{2}

All other quantities are constant for our problem,

     A = k \sqrt{P}

Where k = constant

Here Power become quadruple means four times,

     A = \sqrt{4P}

     A = 2\sqrt{P}

So amplitude changes by factor of 2 means double

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A mass is attached to a spring with an unknown spring constant. The spring gains 10 J of elastic potential energy if stretched b
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For more information, check at: brainly.com/question/1352053.

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