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Naddika [18.5K]
3 years ago
9

A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered

to the string is quadrupled, by what factor does the amplitude change? 16
Physics
1 answer:
just olya [345]3 years ago
5 0

Answer:

Amplitude changes by factor of 2 means double.

Explanation:

Given:

If the power delivered to the string is quadrupled.

From the formula of power transmitted by a sinusoidal wave on a stretched string is,

  P = \frac{1}{2} \mu  \omega ^{2} A^{2}   v

Where \mu = mass per unit length, \omega  = angular speed, A = amplitude, v = wave speed, P = power delivered.

Here we need only two terms power and amplitude.

       P∝ A^{2}

All other quantities are constant for our problem,

     A = k \sqrt{P}

Where k = constant

Here Power become quadruple means four times,

     A = \sqrt{4P}

     A = 2\sqrt{P}

So amplitude changes by factor of 2 means double

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Explanation :

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The prominence consists of colder plasma and this prominence plasma is much more shining and denser as compared to coronal plasma.

Hence, the correct option is (B) Prominence.

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3 years ago
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A magic medallion is suspended from a string inside a compartment of Hogwarts Express which is running straight westwards on hor
Serggg [28]

Answer:

a = 1 m/s²  and

Explanation:

The first two parts can be seen in attachment

We use Newton's second law on each axis

Y axis

      Ty - W = 0        

      Ty = w

X axis

     Tx = m a

With trigonometry we find the components of tension

    Sin θ = Ty / T

    Ty = T sin θ

    Cos θ = Tx / T

    Tx = T cos θ

We calculate the acceleration with kinematics

   Vf = Vo + a t

   a = (Vf -Vo) / t

   a = (20 -10) / 10

   a = 1 m/s²

We substitute in Newton's equations

     

  T Sin θ = mg

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We divide the two equations

  Tan θ = g / a

  θ = tan⁻¹ (g / a)

  θ = tan⁻¹ (9.8 / 1)

  θ = 84º

We see that in the expression of the angle the mass does not appear therefore you should not change the angle

4 0
2 years ago
A car is 200 m from a stop sign and traveling toward the sign at 40.0 m/s. At this time, the driver suddenly realizes that she m
victus00 [196]

Answer:

The acceleration of the car will be a=9600m/sec^

Explanation:

We have given that distance from stop sign s = 200 m

Time t = 0.2 sec

We have to find the constant acceleration

Now from second equation of motion s=ut+\frac{1}{2}at^2

200=40\times 0.2+\frac{1}{2}\times a\times 0.2^2

a=9600m/sec^

So the acceleration of the car will be a=9600m/sec^

6 0
3 years ago
Over a short interval the coordinate of a car in the meters isgiven by x(t) = 27t - 4.0 t3 where time t is in seconds,at the end
wariber [46]

Answer:

5. -24 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s².

mathematically,

a = dv/dt ............................ Equation 1

Where a = acceleration, dv/dt = is the differentiation of velocity with respect to time.

But

v = dx(t)/dt

Where,

x(t) = 27t-4.0t³...................... Equation 2

Therefore, differentiating equation 2 with respect to time.

v = dx(t)/dt = 27-12t²............. Equation 3.

Also differentiating equation 3 with respect to time,

a = dv/dt = -24t

a = -24t .................... Equation 4

from the question,

At the end of 1.0 s,

a = -24(1)

a = -24 m/s².

Thus the acceleration = -24 m/s²

The right option is 5. -24 m/s²

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2 years ago
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Alexeev081 [22]

Answer:

7.05 Volts/m

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L = length of the Nichrome wire = 44 cm = 0.44 m

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E = magnitude of electric field inside the wire

Magnitude of electric field inside the wire is given as

E = \frac{V}{L}

Inserting the values

E = \frac{3.1}{0.44}

E = 7.05 Volts/m

4 0
3 years ago
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