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maria [59]
3 years ago
14

Imagine that a tank is filled with water. The height of the liquid column is 7 meters and the area is 1.5 square meters (m2). Wh

at's the force of gravity acting on the column of water?
A. 68,600 N
B. 102,900 N
C. 110,700 N
D. 73,500 N
Physics
2 answers:
lakkis [162]3 years ago
8 0

Answer:

Force of gravity, F = 102,900 N

Explanation:

It is given that,

Height of the liquid column, h = 7 m

Area of tank, A = 1.5 m²      

We have to find the force of gravity acting on the column of water. Force of gravity is given by :

W = m g .............(1)

Where

m is the mass of an object

g is acceleration due to gravity

Firstly calculating the mass of the tank. It can be calculated suing the definition of density. We know that the density(d) of water is 1 kg/liter

Mass, m = d × V

V = volume = area × height =  1.5 m² × 7 m = 10.5 m³ or 10500 liter

So, m = 1 kg/liter × 10500 liter = 10,500 kg

Equation (1) becomes : W = 10,500 kg × 9.8 m/s²

W = 102,900 N

So, the force of gravity acting on the column of water is 102,900 N. Hence, the correct option is (b).

Crazy boy [7]3 years ago
5 0

Answer:

B. 102,900 N

I remember this question from one of my, test. Really hope this helps..

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What is the concentration of H+ ions at a pH = 2?

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A 10 kg mass car initially at rest on a horizontal track is pushed by a horizontal force of 10 N magnitude. If we neglect the fr
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Answer:

50 m

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A. A land speed car can decelerate at 9.8m/s. How long does it take the car to come to a complete stop from a run of 885 km/hr (
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Answer:

A. 25.08 s

B. 3082.53 m

C. 3×10⁵ m/s²

Explanation:

A. Determination of the time.

This can be obtained as illustrated below:

Acceleration (a) = –9.8 m/s²

Initial velocity (u) = 245.8 m/s

Final velocity (v) = 0 m/s

Time (t) =.?

v = u + at

0 = 245.8 + (–9.8 × t)

0 = 245.8 – 9.8t

Collect like terms

0 – 245.8 = – 9.8t

– 245.8 = – 9.8t

Divide both side by –9.8

t = –245.8 / –9.8

t = 25.08 s

Therefore, it will take 25.08 s for the car to come to a complete stop.

B. Determination of the distance travelled by the car.

Acceleration (a) = –9.8 m/s²

Initial velocity (u) = 245.8 m/s

Final velocity (v) = 0 m/s

Distance (s) =?

v² = u² + 2as

0² = 245.8² + (2 × –9.8 × s)

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0 – 60417.64 = – 19.6s

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Divide both side by –19.6

s = –60417.64 / –19.6

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Thus, the car travelled a distance of 3082.53 m before stopping completely.

C. Determination of the acceleration of the object.

Initial velocity (u) = 0 m/s

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Distance (s) = 0.6 m

Acceleration (a) =?

v² = u² + 2as

600² = 0² + (2 × a × 0.6)

360000 = 0 + 1.2a

360000 = 1.2a

Divide both side by 1.2

a = 360000 / 1.2

a = 300000 = 3×10⁵ m/s²

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Answer:

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