Answer:
![\boxed {\boxed {\sf 0.80 \ mol\ F}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%200.80%20%5C%20mol%5C%20F%7D%7D)
Explanation:
We are asked to find how many moles are in 4.8 × 10²³ fluorine atoms. We convert atoms to moles using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance. In this case, the particles are atoms of fluorine.
We will convert using dimensional analysis and set up a ratio using Avogadro's Number.
![\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}](https://tex.z-dn.net/?f=%5Cfrac%20%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%7D%7B%201%20%5C%20mol%20%5C%20F%7D)
We are converting 4.8 × 10²³ fluorine atoms to moles, so we multiply the ratio by this number.
![4.8 \times 10^{23} \ atoms \ F *\frac {6.022 \times 10^{23} \ atoms \ F}{ 1 \ mol \ F}](https://tex.z-dn.net/?f=4.8%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%20%2A%5Cfrac%20%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%7D%7B%201%20%5C%20mol%20%5C%20F%7D)
Flip the ratio so the units of atoms of fluorine cancel each other out.
![4.8 \times 10^{23} \ atoms \ F *\frac { 1 \ mol \ F}{6.022 \times 10^{23} \ atoms \ F}](https://tex.z-dn.net/?f=4.8%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%20%2A%5Cfrac%20%7B%201%20%5C%20mol%20%5C%20F%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%5C%20atoms%20%5C%20F%7D)
![4.8 \times 10^{23} *\frac { 1 \ mol \ F}{6.022 \times 10^{23} }](https://tex.z-dn.net/?f=4.8%20%5Ctimes%2010%5E%7B23%7D%20%20%2A%5Cfrac%20%7B%201%20%5C%20mol%20%5C%20F%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%7D)
Condense into 1 fraction.
![\frac { 4.8 \times 10^{23} }{6.022 \times 10^{23} } \ mol \ F](https://tex.z-dn.net/?f=%5Cfrac%20%7B%204.8%20%5Ctimes%2010%5E%7B23%7D%20%7D%7B6.022%20%5Ctimes%2010%5E%7B23%7D%20%7D%20%5C%20mol%20%5C%20F)
Divide.
![0.7970773829 \ mol \ F](https://tex.z-dn.net/?f=0.7970773829%20%5C%20mol%20%5C%20F)
The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we found, that is the hundredths place. The 7 in the thousandths tells us to round the 9 in the hundredths place up to a 0. Then, we also have to round the 7 in the tenths place up to an 8.
![0.80 \ mol \ F](https://tex.z-dn.net/?f=0.80%20%5C%20mol%20%5C%20F)
4.8 × 10²³ fluorine atoms are equal to <u>0.80 moles of fluorine.</u>
Answer:
our bodies will dehydrate causing us to die a dreadfully excruciating painful death
1128 is the momentum for this. i think
Slow it down - I believe?
First, find the number of moles for each element. The molar
mass for nitrogen is 14 g/mol and that of hydrogen is 1 g/mol.
1.40 g N / 14 g/mol = 0.1 mol N
0.20 g H / 1 g/mol = 0.2 mol H
Find the mole ratio. Divide both numbers with the much lower
value. In this case, it is 0.1 mol N.
For N: 0.1 ÷ 0.1 = 1
For H: 0.2÷0.1 = 2
Thus, the empirical formula is
.