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3 years ago

I don't know how to delete this lol.

Chemistry

1 answer:

Sergeu [11.5K]3 years ago

7 0

Answer:

oh all u do is say that u w..anna quick this question

Explanation:

well thats what i do

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In the Bohr model of the hydrogen atom, the energy required to excite an electron from n = 2 to n = 3 is _______________ the ene

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Answer:

greater than

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3 years ago

How many sig figs are there<br> 5.00000008

djverab [1.8K]

Answer:

2 sig figs.

Explanation:

Sig Fig Rules:

Any non-zero digit is a significant figure.

Any zeros between 2 non-zero digits are significant figures.

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4 years ago

Calculate the wavelength of a photon having energy of 1.257 X 10-24 joules. (Planck’s constant is 6.626 x 10-34 joule seconds; t

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$E=h\nu\\\\
\nu=\frac{c}{\lambda} \ \ \ \Rightarrow E=\dfrac{hc}\lambda}\\\\
\lambda=\dfrac{hc}{E}=\dfrac{6,626*10^{-34}Js*2,998*10^{8}\dfrac{m}{s}}{1,257*10^{-24}J}=15,803*10^{\frac{-34+8}{-24}}m=\\\\\\=15,803*10^{-2}m=1,5803*10^{-1}m$

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3 years ago

Sarah's class is studying soils. Her teacher, Ms. Jones, stated that plants will growth in any soil type. Students in Sarah's cl

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4 years ago

Read 2 more answers

In a galvanic cell,a oxidation occurs at the (name of electrode)b.the cathode is the (sign) electrodec.cations flow in solution

Tatiana [17]

Answer: a) anode

b) positive

c) cathode

d) anode to cathode

Explanation:

Galvanic cell is defined as a device which is used for the conversion of the chemical energy produces in a redox reaction into the electrical energy.

In the galvanic cell, the oxidation occurs at an anode which is a negative electrode and the reduction occurs at the cathode which is a positive electrode. Thus the electrons are produced at anode and travel towards cathode.

Due to loss of electrons at anode, positive charge in concentrated in anode and negative charge is concentrated in cathode. To balance these charges , positive ions or cations from salt bridge move towards cathode and negative ions or anions from salt bridge move towards anode.

The balanced two-half reactions will be:

Oxidation half reaction : $M(s)\rightarrow M^{n+}(aq)+ne^-$

Reduction half reaction : $X^{n+}(aq)+ne^-\rightarrow X(s)$

Thus the overall reaction will be,

$M(s)+X^{n+}(aq)\rightarrow M^{n+}(aq)+X(s)$

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4 years ago