What will happen if a peeled banana is put on a hotplate?

What are your main fears about this class (if any)?

netineya [11]

This is based on your personal opinion lol but ig you can say public speaking

8 0

3 years ago

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The density of methanol is 0.7918g/mL. Calculate the mass of 89.9mL of this liquid.

Novosadov [1.4K]

The mass is 71.2 g.

Mass = 89.9 mL × $\frac{0.7918 g}{1 mL}$ = 71.2 g

4 0

3 years ago

In a polar covalent bond, the distribution of common electrons are

amid [387]

In a polar covalent bond, the distribution of common electrons are not shared evenly due to a greater positive charge from one atom's nucleus.Oct 30, 2016

3 0

2 years ago

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Ethylenediamine (en) forms an octahedral complex with Ni2+(aq) with the formula [Ni(en)3]2+. Ni2+(aq) + 3 en ⇌ [Ni(en)3]2+(aq) K

yawa3891 [41]

Answer:

$3.125\times 10^{-19} mol/L$ is the concentration of $Ni^{2+}(aq)$ in the solution.

Explanation:

$Ni^{2+}(aq) + 3 en\rightleftharpoons [Ni(en)_3]^{2+}(aq)$

Concentration of nickel ion = $[Ni^{2+}]=x$

Concentration of nickel complex= $[[Ni(en)_3]^{2+}]=\frac{0.16 mol}{2 L}=0.08 mol/L$

Concentration of ethylenediamine = $[en]=\frac{0.80 mol}{2 L}=0.40 mol/L$

The formation constant of the complex = $K_f=4.0\times 10^{18}$

The expression of formation constant is given as:

$K_f=\frac{[[Ni(en)_3]^{2+}]}{[Ni^{2+}][en]^3}$

$4.0\times 10^{18}=\frac{0.08 mol/L}{x\times (0.40 mol/L)^3}$

$x=\frac{0.08 mol/L}{4.0\times 10^{18}\times (0.40 mol/L)^3}$

$x=3.125\times 10^{-19} mol/L$

$3.125\times 10^{-19} mol/L$ is the concentration of $Ni^{2+}(aq)$ in the solution.

6 0

3 years ago

For each of the following formulas, write the

ankoles [38]

Answer:

(a) Potassium 3; phosphorus 1; oxygen 4

(b) Aluminium 3; oxygen 9; hydrogen 9

(c) Iron 10; sulfur 15; oxygen 60

Explanation:

(a) K₃PO₄

In one formula unit of K₃PO₄ , there are three atoms of potassium (K), one atom of phosphorus (P), and four atoms of oxygen (O).

In two formula units there are

Potassium — six atoms

Phosphorus — two atoms

Oxygen — eight atoms

(b) Al(OH)₃

In one formula unit of Al(OH)₃, there is one atom of aluminium (Al), three atoms of O, and three atoms of Hydrogen (H).

In three formula units there are

Aluminium — three atoms

Oxygen — nine atoms

Hydrogen — nine atoms

(c) Fe₂(SO₄)₃

In one formula unit of Fe₂(SO₄)₃, there are two atoms of iron (Fe), three atoms of sulfur (S), and 12 atoms of O.

In five formula units there are

Iron — 10 atoms

Sulfur — 15 atoms

Oxygen — 60 atoms

5 0

3 years ago