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sweet [91]
2 years ago
9

Which component is missing from the process of cellular respiration? Glucose ________ → Carbon Dioxide Water Energy Sunlight Sug

ar Oxygen Carbon.
Chemistry
1 answer:
Marrrta [24]2 years ago
3 0

Cellular Respiration is the process of breakdown of sugar molecules, especially glucose to yield energy in the form of ATP. Every organism undergoes cellular respiration.

<h3>What are the requirements of cellular respiration?</h3>

  • Cellular respiration can take place in the presence of oxygen (aerobic) and in the absence of oxygen (anaerobic) to yield energy.

  • In aerobic cellular respiration, the glucose is broken down in the presence of oxygen to yield energy, carbon dioxide, and water. The process is seen in many plants and animals.

Thus, cellular respiration is the process of the breakdown of glucose in the presence or absence of oxygen to yield energy.

Learn more about cellular respiration here:

brainly.com/question/12671790

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2 FONS
stiv31 [10]

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4)  = F1/4

7 0
3 years ago
The formula for cocaine is C17H21N04. What is the percentage of carbon in the
PolarNik [594]
The correct answer is d
6 0
4 years ago
Read 2 more answers
It takes
poizon [28]

The maximum wavelength that can break a Cl-Cl bond is 494 nm.

<em>Energy to break 1 Cl-Cl bond </em>

Energy = (242 kJ/1 mol) × (1000 J/1 kJ) × (1 mol/6.022 × 10²³ bonds)

= 4.019 × 10⁻¹⁹ J/bond

<em>Wavelength of photon </em>

<em>E</em> = h<em>f</em> = (h<em>c</em>)/λ

λ = (h<em>c</em>)/E = (6.626 × 10⁻³⁴ J × 2.998 × 10⁸ m·s⁻¹)/(4.019 × 10⁻¹⁹ J) = 4.94 × 10⁻⁷ m = 494 nm

6 0
4 years ago
The term "precision" BEST refers to which of the following?
strojnjashka [21]

Answer:

A.

Explanation:

the term precision refers to something that is has the most quality or good condition, being precise and exact.

5 0
3 years ago
Read 2 more answers
6. A student was conducting an experiment to find the volume of a spherical metal object. He placed it in the graduated cylinder
Sergio039 [100]
<h3>Answer:</h3>

                No, it wouldn't affect the volume.

<h3>Explanation:</h3>

                         Let us suppose the masses of metal object before and after shape change to be,

                              Mass before shape change  =  2.5 g

                                Mass after shape change  =  2.5 g

As the shape change has not affected on the mass so in both states it will remain 2.5 g.

Secondly, as density will remain same for both states because it is intensive property of a particular matter and is considered a characteristic property. Hence, it will also remain constant before and after shape change. Assume the density to be 2 g.mL⁻¹.

Therefore the volume calculated will be,

Before shape change:

                                   Volume-1  =  Density × Mass

                                   Volume-1  =  2 g.mL⁻¹ × 2.5 g

                                   Volume-1  =  5 mL

After shape change:

                                   Volume-2  =  Density × Mass

                                   Volume-2  =  2 g.mL⁻¹ × 2.5 g

                                   Volume-2  =  5 mL

<h3>Conclusion:</h3>

                  The volume is not affected by changing shape. Hence, after shape change the object will be having a volume of 5 mL.

8 0
3 years ago
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