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White raven [17]
3 years ago
5

What is the slope of the line that passes through the points (-10,-8) and (-8,-16)?

Mathematics
1 answer:
ki77a [65]3 years ago
3 0

To find the slope of this line we will use the slope formula, which is:

m = \dfrac{y_2 - y_1}{x_2 - x_1}

(Where (x_1, y_1) and (x_2, y_2) are points on the line)


To find our answer to this problem, we can simply substitute the values we are given:

m = \dfrac{-16 - (-8)}{-8 - (-10)} = \dfrac{-16 + 8}{-8 + 10} = \dfrac{-8}{2} = -4


The slope of the line is -4.

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Step-by-step explanation:

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8 0
3 years ago
The confidence interval is to .
navik [9.2K]

Answer:

See below

Step-by-step explanation:

The purpose of the confidence interval is to give a range of where the true value of a parameter lies given a confidence level.

8 0
3 years ago
the lengths of 2 sides of a triangle are shown. side 1: 3x2 - 4x - 1. side 2: 4x - x2 + 5. the perimeter is 5x3 - 2x2 + 3x - 8
BigorU [14]

Answer:

A. 2x^2+4

B. 5x^3 - 4x^2 + 3x - 12

C. Yes

Step-by-step explanation:

Given:

Side 1=3x^2-4x-1

Side 2=4x-x^2+5

Perimeter=5x^3-2x^2+3x-8

Perimeter=side 1 + Side 2 + Side 3

A. Total lenght of the two sides

Side 1 + Side 2=(3x^2-4x-1) + (4x-x^2+5)

=3x^2 - 4x - 1 + 4x - x^2 + 5

=3x^2 - x^2 - 4x + 4x - 1 + 5

=2x^2+4

B. Length of the third side

Perimeter=side 1 + Side 2 + Side 3

Recall,

Side 1 + side 2=2x^2+4

Perimeter= (side 1 + Side 2) + Side 3

5x^3-2x^2+3x-8 = 2x^2+4 + side 3

5x^3-2x^2+3x-8 - (2x^2+4) = side

3

5x^3 - 2x^2 + 3x - 8 - 2x^2 - 4 = Side 3

5x^3 - 2x^2 - 2x^2 + 3x - 8 - 4 = Side 3

=5x^3-4x^2+3x-12

Side 3= 5x^3 - 4x^2 + 3x - 12

C. Yes, addition and subtraction of polynomial of the same degree will give result of the same degree or lower degree

6 0
3 years ago
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Anastaziya [24]
For the line y=4x+5 the parent function is y=x
7 0
3 years ago
Solve for x. 6x + 9 + 4x + 2 = 21
Pie

Answer:

6x + 9 + 4x + 2 = 21 \\ 6x + 4x + 11 = 21 \\ 10x + 11 = 21 \\ 10x = 21 - 11 \\ 10x = 10 \\ x =  \frac{10}{10}  \\ x = 1

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3 years ago
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