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2 years ago

Solve the problem. Round as appropriate.

Mathematics

1 answer:

Monica [59]2 years ago

8 0

Answer:

i need the points

Step-by-step explanation:

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8(C - 9) = 6(20 - 12) - 40

krek1111 [17]

Answer:

All Real Numbers

Step-by-step explanation:

Any value of c makes the equation true.

Interval Notation

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3 years ago

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Two cylinders are similar. The radius of cylinder a is 5.6 in. The radius of cylinder b is 1.4 in. If the hwight of cylinder b i

sleet_krkn [62]

The answer is 16in.

Let the radius and height of cylinder A be Ra and Hb respectively and the radius and height of cylinder B be Rb and Hb respectively.

Using similar shapes:
Ra/Ha= Rb/Hb
5.6/Ha=1.4/4
Ha=(4×5.6)/1.4
Ha=22.4/1.4
Ha=16in

6 0

3 years ago

Choose the best estimate for the length of a piece of notebook paper.

Fynjy0 [20]

Answer:

11 in

Step-by-step explanation:

Standard paper is 11 x 8 inches

5 0

3 years ago

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X=? Y=6 75 degree angle at (0,0) What is X?

choli [55]

Answer:

$X=12-6\sqrt{3}=1.6077$

Step-by-step explanation:

Given that $Y=6$

$\tan(75)=\frac{Y}{X} \\X=\frac{Y}{\tan(75)}=Y\cot75=6\cot75 \\\\Calculate \ \cot(75)\\\tan(75)=\tan(45+30)=\frac{\tan45+\tan30}{1-\tan45 \cdot \tan30} =\frac{1+\frac{1}{\sqrt{3} } }{1-\frac{1}{\sqrt{3} } } \\\tan75=\frac{\sqrt{3}+1 }{\sqrt{3}-1 } =2+\sqrt{3} \\\cot75=\frac{1}{2+\sqrt{3} } =\frac{2-\sqrt{3} }{2^2-3} =2-\sqrt{3} \\\\Hence\\X=6\cot75=6 \cdot(2-\sqrt{3})\\X=12-6\sqrt{3} \approx1.6077$

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3 years ago

Simplify: 5(8r) + 3(4r)

Lady_Fox [76]

5 * 8r = 40r
3 * 4r = 12r
40r + 12r = 52r
Solution: 52r

4 0

3 years ago