I'll have Martin as X and Melvin as Y.
So the equation for X is, 15(starting point) and +5 every set.
Here's a table
________________
The amount of sets|Lbs -------->This one's for Y
__________________ ________________
0 | 15 0 | 60
1 | 20 1 | 50
2 | 25 2 | 40
3 | 30 3 | 30
4 | 35
On the third set, tables help. I'll do the first question in the comments
Answer:
Sorrry i dont know
Step-by-step explanation:
Answer:
(1.5,2.5)
Step-by-step explanation:
f(x) = 2x^2 - 6x + 7
Take the first derivative and set it equal to 0 (the slope is 0 at the vertex)
f'(x) = 4x -6
0 = 4x - 6
4x = 6
x = 3/2 or 1.5
If x = (3/2), then y = 2(3/2)^2 - 6(3/2) + 7
y = 2(9/4) - 18/2 + 7
y = (9/2) - 2
y = 2.5
See attached graph.
<h3>
Answer: -0.196</h3>
======================================================
Explanation:
We're conducting a one proportion Z test.
The hypothesized population proportion is p = 0.53, which is not to be confused with the p-value (unfortunately statistics textbooks seem to overuse the letter 'p'). Luckily this problem is not asking for the p-value.
The sample population proportion is
phat = x/n = 41/79 = 0.518987 approximately
The standard error (SE) is
SE = sqrt(p*(1-p)/n)
SE = sqrt(0.53*(1-0.53)/79)
SE = 0.056153 approximately
Making the test statistic to be
z = (phat - p)/(SE)
z = (0.518987 - 0.53)/0.056153
z = -0.19612487311452
z = -0.196
Which is approximate and rounded to 3 decimal places.
Solving this problem simply only requires us the knowledge
of multiplication.
So we are initially given that there are 5 craft sticks.
So if we need four times that amount, that is written as:
5 x 4
Which is equal to 20
<span>So Jack needs 20</span>
