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velikii [3]
3 years ago
11

*** PLEASE HELP IM TIMED

Mathematics
2 answers:
mart [117]3 years ago
5 0
The first one because it’s the actual formula for a sphere and it has pie at the end because we are solving for a sphere
pychu [463]3 years ago
5 0

Archimedes solved this in his famous book <em>Sphere and Cylinder</em> in 225 BC.  The result is reportedly on his tombstone.

The ratio of the volume of the radius r sphere to the cylinder radius r, height 2r is

\dfrac 2 3

The same ratio is the ratio of the surface area of the sphere to that of the cylinder (including the ends).

Answer: Last choice

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Janie walks 1 mile to get to a running track.she then runs at a speed of 3.5 miles per hour.Which linear models represents the t
MrMuchimi

Answer:

d = 3.5t + 1

Step-by-step explanation:

The linear function would have to multiply the speed she runs at the track by the number of hours that she spent running. Then it should add this amount to the 1 mile that she walked to get to the track. If we use the variable d as the total distance that she ran and walked, and the variable t to represent time then we would create the following linear function/model.

d = 3.5t + 1

3 0
3 years ago
Polynomial division<br>(4x^2 +7x +6) ÷(x+ 2)​
jolli1 [7]

Answer:

4x2 + 7x - 6

 ————————————

    x - 2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What percentage of the semi circle is shaded? <br>​
mezya [45]

The percentage of the semicircle shaded section is approximately 23,606 %.

The percentage of the area of the semicircle is equal to the ratio of the semicircle area minus the half-cross area to the semicircle area. In other words, we have the following expression:

r = \left(\frac{A_{s}-A_{h}}{A_{s}} \right)\times 100\,\%

r = \left(1-\frac{A_{h}}{A_{s}} \right)\times 100\,\% (1)

Where:

  • A_{h} - Area of the half cross, in square centimeters.
  • A_{s} - Area of the semicircle, in square centimeters.
  • r - Percentage of the shaded section of the semicircle.

And the percentage of the shaded section is:

r = \left[1-\frac{4 \cdot (2\,cm)^{2}+4\cdot \left(\frac{1}{2} \right)\cdot (2\,cm)^{2}}{0.5\cdot \pi\cdot (16\,cm^{2}+4\,cm^{2})} \right]\times 100

r \approx 23.606\,\%

The percentage of the semicircle shaded section is approximately 23,606 %.

We kindly invite to check this question on percentages: brainly.com/question/15469506

3 0
2 years ago
The melting point of mercury is -36°F and its boiling point is 672°F. what is the difference between the melting and boiling poi
Ira Lisetskai [31]

Step-by-step explanation:

644

672- 36

=644

5 0
2 years ago
please help me please please please please please please please please please please please please please please please please p
IRISSAK [1]

Answer:

3.) 7

4.) 5

5.) 25

6.) 2/3

7.) 9

8.) 24

5 0
3 years ago
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