Eras and then smaller periods based on geologic and biologic events that occurred during those times. According to geological time scale, there are six eras from the beginning some periods of few eras & then period is classified into smaller units called "epoch"
In short, Your Answer would be Option B
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Huh huh what? ¿Can’t you translate?
Answer:
29.4 N/m
0.1
Explanation:
a) From the restoring Force we know that :
F_r = —k*x
the gravitational force :
F_g=mg
Where:
F_r is the restoring force .
F_g is the gravitational force
g is the acceleration of gravity
k is the constant force
xi , x2 are the displacement made by the two masses.
Givens:
<em>m1 = 1.29 kg</em>
<em>m2 = 0.3 kg </em>
<em>x1 = -0.75 m </em>
<em>x2 = -0.2 m </em>
<em>g = 9.8 m/s^2 </em>
Plugging known information to get :
F_r =F_g
-k*x1 + k*x2=m1*g-m2*g
k=29.4 N/m
b) To get the unloaded length 1:
l=x1-(F_1/k)
Givens:
m1 = 1.95kg , x1 = —0.75m
Plugging known infromation to get :
l= x1 — (F_1/k)
= 0.1
Sample Response: No image will be formed because the rays will not converge to or diverge from a common point.
-- Take a sample of the first fluid.
-- Measure its mass.
-- Measure its volume.
-- Divide its mass by its volume.
This gives you the density of the first fluid.
-- Take a sample of the second fluid.
-- Measure its mass.
-- Measure its volume.
-- Divide its mass by its volume.
This gives you the density of the second fluid.
You want their average ?
OK
-- Add (Density of the first fluid) + (Density of the second fluid).
-- Divide the sum by 2 .
Now you have the average of the two densities.
Note:
That's NOT necessarily the density of a mixture when you
pour some of fluid-1 and fluid-2 into a jar. The density of the
fluid in the jar is going to depend on how much of each fluid is
in there.
I started to calculate how much of each one has to be there in order
for the density of the mixture to be equal to the average of their two
densities. But then I sat up straight, asked myself "Why ? !" .
Then I stopped, and went into the kitchen and ate some meatloaf.