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erik [133]
4 years ago
6

Why do raindrops fall with a constant speed during the later stages of their descents?

Physics
1 answer:
BartSMP [9]4 years ago
6 0
Firstly they have a acceleration downwards due the force downwards due they gravitational field acting on it's mass.
as it falls it gains speed, and as it gains speed the air Resistance which is a upward force actin on the drop increases, eventually the rain drop's upward and downward forces are balanced and hence there is no RESULTANT force therefore no acceleration, so the drops falls in constant speed (terminal verlocity is a better term)

Are you wondering that why is the raindrop still moving given that the forces are balanced? If so according to Newton's 1st law an object will keep moving or Remain at rest until a RESULTANT force acts on it.
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gregori [183]

As we know that total work done by a force is given by

W = F.d

W = Fdcos\theta

so it is product of force and displacement along same direction

as we can write it as

W = (Fcos\theta)(d)

so it must be the product of force and displacement in same directions so correct answer must be

<u>B. in the same direction as the displacement vector and the motion.</u>

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3 years ago
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AnswAnswer This!!!!!!<br> I'll give brainliest to whoever gets it right.
Gala2k [10]
Answer: 1.0 mol

8/2 = 4/2 = 2/2 = 1

8 0
3 years ago
Are bases chemically the same as acids true or false
Inessa [10]

Answer:

True

Explanation:

True\

I'm not sure but i think it is true la

6 0
3 years ago
What must the diver's minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, wh
Dafna1 [17]

Answer:

1.08 m/s

Explanation:

This can be solved with two steps, first we need to find the time taken to fall 9.5 m, then we can divide the horizontal distance covered with time taken to calculate the velocity.

Time taken to fall 9.5 m

vertical acceleration = a = 9.8 m/s^2.

vertical velocity = 0, (since there is only horizontal component for velocity, )

distance traveled  s = 9.5 m.

Substituting these values in the equation

s= u \timest+0.5at^{2}

t= \sqrt{\frac{2s}{g} }

t=\sqrt{\frac{2\times9.5}{9.8} }

⇒ t= 1.392 sec

Velocity needed

We know the time taken (1.392 s) to travel 1.5 m,

So velocity = 1.5 m / 1.392 s = 1.08 m/s

hence velocity of the diver must be at least 1.08 m/s

4 0
3 years ago
A 1.23 x 10^3 kilogram car is traveling east at 25 meters per second. The brakes are applied and the car is brought to rest in 5
ahrayia [7]

Answer:

\text{Magnitude: }30,000\:\text{Ns},\\\text{Direction: opposite direction of car's movement}}

Explanation:

*Edit: The original question states a mass of 1.23\cdot 10^3\:\text{kg}. Since the, the poster has corrected it to 1.20\cdot 10^3\:\text{kg} and therefore the answers have been change to account for the typo.

The impulse-momentum theorem states that the impulse on a object is equal to the change in momentum of the object.

Therefore, we have the following equation:

F\Delta t=\Delta p, where F\Delta t is impulse (another way to find impulse) and \Delta p is change in momentum.

Because the car is being slowed to a rest, its final velocity will be zero, and therefore its final momentum will also be zero. Since momentum is given as p=mv, the car's change in momentum is 1.20\cdot 10^3\cdot 25-0=1230\cdot 25=30,000\:\text{kgm/s}.

As we wrote earlier, this is also equal to the magnitude of impulse on the object. The time it takes to stop the car is actually irrelevant to finding the total impulse. However, if we were to calculated the average applied force on the car, we would need how long it takes to bring it to rest (refer to F\Delta t).

The direction of the impulse must be exactly opposite to the car's direction, since we are slowing it to a stop.

Therefore, the impulse on the car is \boxed{30,750\:\text{Ns, opposite direction of car's movement}}.

3 0
3 years ago
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