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Savatey [412]
3 years ago
12

The graph in Figure 4.15 shows the position and time for two runners in a race. Who has the faster speed, Robin or Joel? Explain

how to answer this question without doing calculations.

Physics
1 answer:
Burka [1]3 years ago
4 0

Answer:

Joel has the faster speed.

Explanation:

Joel has a steeper slope on the graph. The steeper a slope is, the faster speed will be. Therefore, Joel's slope is steeper which increases overall speed.

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How many stars are contained in the milking way galaxy A) 0 b)1 c) billions d)infinite
skelet666 [1.2K]

Answer:

c) billions

Explanation:

there are more than 0 stars, because our sun is a star

and  there are more than one because the milky way has a lot of suns

there aren't infinite because the milky way is finite it has some volume and even you made the smallest star possible you wouldn't have infinite stars

so the only option is billions

7 0
3 years ago
The pressure of 4.20 L of an ideal gas in a flexible container is decreased to one-third of its original pressure, and its absol
Dmitrij [34]

Answer:

6.30 L

Explanation:

P1 = P, V1 = 4.20 L, T1 = T

P2 = P/3, V2 = ?, T2 = T/2

Where, V2 be the final volume.

Use ideal gas equation

\frac{P_{1}\times V_{1}}{T_{1}} = \frac{P_{2}\times V_{2}}{T_{2}}

V_{2} = \frac{P_{1}}{P_{2}}\times\frac{T_{2}}{T_{1}}\times V_{1}

By substituting the values, we get

V2 = 6.30 L

8 0
3 years ago
A car starting from rest accelerates at a constant 2.0 m/s2 for 10 s. It then travels with constant speed it has achieved for an
Anon25 [30]

Answer:

The total distance will be 400 m.

Explanation:

For portion AB:

Acceleration = 2m/s^2

t= 10 s

Car start from rest , u=0 m/s

We know that

S=ut+\dfrac{1}{2}at^2

S=0+\dfrac{1}{2}\times 2\times 10^2

S= 100 m.

For portion BC:

V= u + at

V=0 + 2 x 10

V= 20 m/s

In this portion car moves with constant velocity  20 m/s for 10 s.

So distance S= V x t

S=20 x 10 =200 m.

For portion CD:

The velocity at point C will be 20 m/s

In this portion the final speed of car will be zero because given that at final car come to rest.

So the acceleration will be in the negative direction to stop the car.

We know that

v^2=u^2-2aS

0=20^2-2\times 2\times S

S=100 m

The total distance AD=AB + BC+ CD

AD=100 +200 + 100 m

AD=400 m.

The total distance will be 400 m.

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Three light bulbs are wired in series. What happens if one of these light bulbs burn out
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