All categories

3 years ago

A sample of lemon juice is found to have a pH of 2.3. What is the concentration of hydrogen ions in the lemon juice?

Chemistry

1 answer:

Elenna [48]3 years ago

7 0

Answer: It's equal to 10^(-2.3), or 0.00501 M, or 5.01 * 10^-3 moles/Liter

Explanation:

Well, pH = - log[H+]

Or, in words, pH is equal to -1 multiplied by the logarithm (base 10) of the hydrogen ion concentration. So you have 2.3 = -log[H+]. We want to isolate the H+, so let's start simplifying the right hand side of the equation. First, we multiply both sides by -1. -2.3=log[H+] Now, the definition of a logarithm says that if the log (base 10) of [H+] is -2.3, then 10 raised to the -2.3 power is [H+] So on each side of the equation, we raise 10 to the power of that side of the equation. 10^(-2.3) = 10^(log[H+]) and because 10^log cancels out... 10^(-2.3) = [H+] Now we've solved for [H+], the hydrogen ion concentration!

You might be interested in

When completing an experiment, results will be much more accurate if multiple trials are completed and the results averaged. TRU

grandymaker [24]

<span>When completing an experiment, results will be much more accurate if multiple trials are completed and the results averaged. True. That's because you may get different results each time. </span>

5 0

3 years ago

Read 2 more answers

a sample that has a half life of 45 years take ____ for the count rate to drop from 600 cpm to 150 cpm

Bond [772]

Answer:

90yrs

Explanation:

Half life is the time taken for half of an original radioactive material to decay by half.

For the sample;

Half - life = 45yrs

Original amount = 600cpm

Start Number of atoms

0yrs 600cpm

First half life

45yrs 300cpm

Second half life

90yrs 150cpm

5 0

3 years ago

The quantities 1 mol and 22.4 L can be used in conversion factors that change moles to volume and volume to moles at STP.

Luden [163]

True. Bc 1 mol and 22.4 L=23.4

6 0

3 years ago

Read 2 more answers

The diagram below shows students set-up for the preparation and collection of oxygen gas

dmitriy555 [2]

Answer:

iodine sodium preocide

Explanation:

hang hsudb

3 0

3 years ago

What volume (ml) of fluorine gas is required to react with 1. 28 g of calcium bromide to form calcium fluoride and bromine gas a

Alexandra [31]

144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

<h3>What is Ideal Gas Law ? </h3>

The ideal gas law states that the pressure of gas is directly proportional to the volume and temperature of the gas.

PV = nRT

where,

P = Presure

V = Volume in liters

n = number of moles of gas

R = Ideal gas constant

T = temperature in Kelvin

Here,

P = 1 atm [At STP]

R = 0.0821 atm.L/mol.K

T = 273 K [At STP]

Now first find the number of moles

F₂ + CaBr₂ → CaF₂ + Br₂

Here 1 mole of F₂ reacts with 1 mole of CaBr₂.

So, 199.89 g CaBr₂ reacts with = 1 mole of F₂

1.28 g of CaBr₂ will react with = n mole of F₂

$n = \frac{1.28\g \times 1\ \text{mole}}{199.89\ g}$

n = 0.0064 mole

Now put the value in above equation we get

PV = nRT

1 atm × V = 0.0064 × 0.0821 atm.L/mol.K × 273 K

V = 0.1434 L

V ≈ 144 mL

Thus from the above conclusion we can say that 144 mL of fluorine gas is required to react with 1.28 g of calcium bromide to form calcium fluoride and bromine gas at STP.

Learn more about the Ideal Gas here: brainly.com/question/20348074

#SPJ4

4 0

2 years ago