Answer:
R = 3.88 m
Explanation:
As the Chinook salmon leaves the water till it gets back into the water it is performing a projectile motion with the following parameters:
V₀ = Launch Speed = 6.7 m/s
θ = Launch Angle = 29°
R= Range of Projectile= Horizontal Distance Covered by Chinook salmon= ?
The value of the range of a projectile is given by the following formula:
R = (V₀² Sin 2θ)/g
R = [(6.7 m/s)² Sin {(2)(29°)}/(9.8 m/s²)]
R = [(6.7 m/s)² Sin (58°)/(9.8 m/s²)]
<u>R = 3.88 m</u>
Explanation:
It is given that,
Spring constant, k = 81 N/m
We need to find the force required to :
(a) Compress the spring by 6 cm i.e. x₁ = 6 cm = -0.06 m
It can be calculated using Hooke's law as :
F = - k(-x₁)

F = 4.86 N
(b) Expand the spring by 17 cm i.e. x₂ = 17 cm = +0.17 m
So, F = -kx₂

F = -13.77 N
Hence, this is the required solution.
Answer:

Explanation:
ΣF=ma
The two forces at play are the force applied and the force due to friction. As they are opposing forces set the direction being pushed as the positive in the x direction. the equation you come out with is 60 - 15=(15)A (we know mass to be 15kg). Solve for 3 m/s^2.
Newton’s 3rd Law: for every action there is an equal but opposite reaction.
Assuming that the box is motionless, we can say the force is -20N