<span>T(t)=60+140<span>e<span>−0.075t</span></span></span>
<span>T(12)=60+140<span>e<span>−0.075∗12</span></span></span>
<span>T(12)=60+140<span>e<span>−0.9</span></span></span>
<span><span>T(12)=60+140(0.4065696597)
        =116.84
 So the temperature will be approximately 117 degrees</span></span>
        
             
        
        
        
It can be measured by an ammeter.
        
             
        
        
        
Acceleration a=3m/s^2
time t= 4.1seconds
Final velocity V= 55km/h
initial velocity U= ?
First convert V to m/s
36km/h=10m/s
55km/h= 55*10/36=15.28m/s
Using the formula V= U+at
U= V-at
U= 15.28-3*4.1=15.28-12.3=2.98m/s
Initial velocity U= 2.98m/s or 10.73km/h (Using the conversion rate 36km/h=10m/s)
        
             
        
        
        
Answer: 3 A
Explanation:
According to<u> Ohm's law</u>:  
 
 
Where:
 is the voltage
 is the voltage
 is the resistance of the resistor
 is the resistance of the resistor
 is the electric current (the value we want to find)
 is the electric current (the value we want to find)
Isolating  :
:


Finally:
