The IUPAC name for a binary covalent compound will lack roman numerals.
Binary covalent compound comprises of two elements which forms a
compound through the sharing of electrons.
The sharing of electrons is referred to as covalent bonding and naming such
compounds require prefixes such as mono-, di- , tri- etc.
The standard method of naming these compounds should be with the
prefixes and not with the roman numerals.
An example is carbon(IV)oxide which is wrong in IUPAC naming.
Read more on brainly.com/question/16731560
the answer is magnesium chloride. it is an ionic compound because Mg forms ionic bond to Cl by donating its valence electrons to two Cl atoms. :)
ANSWER:
0.94 cm
EXPLANATION
From the question,
![M=56.3g \\ D = 6.73g/ {cm}^{3} \\ l = 12.0cm](https://tex.z-dn.net/?f=M%3D56.3g%20%5C%5C%20D%20%3D%206.73g%2F%20%7Bcm%7D%5E%7B3%7D%20%5C%5C%20l%20%3D%2012.0cm)
![D = \frac{M}{V}](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7BM%7D%7BV%7D%20)
This implies that,
![M=V \times D.......1](https://tex.z-dn.net/?f=%20M%3DV%20%5Ctimes%20D.......1)
But volume is given by the relation;
![V = \frac{\pi {d}^{2} l}{4}.......2](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cfrac%7B%5Cpi%20%7Bd%7D%5E%7B2%7D%20l%7D%7B4%7D.......2)
Substituting equation 2 into equataion 1 and making d the subject.
![M= \frac{\pi {d}^{2} l D}{4}](https://tex.z-dn.net/?f=%20M%3D%20%5Cfrac%7B%5Cpi%20%7Bd%7D%5E%7B2%7D%20l%20D%7D%7B4%7D)
Multiplying both side of the equation by
![\frac{4}{\pi \: lD}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B%5Cpi%20%5C%3A%20lD%7D)
gives;
![{d}^{2} = \frac{4M}{{\pi \: lD}}](https://tex.z-dn.net/?f=%20%7Bd%7D%5E%7B2%7D%20%3D%20%5Cfrac%7B4M%7D%7B%7B%5Cpi%20%5C%3A%20lD%7D%7D)
square root both sides gives;
![d = \sqrt{\frac{4M}{{\pi \: lD}}} ....3](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cfrac%7B4M%7D%7B%7B%5Cpi%20%5C%3A%20lD%7D%7D%7D%20....3)
substituting the values of M,V,D and l into equation 4 to get the value for d
![d = \sqrt{\frac{4 \times 56.3}{{\pi \: \times 12 \times 6.73}}}](https://tex.z-dn.net/?f=d%20%3D%20%5Csqrt%7B%5Cfrac%7B4%20%5Ctimes%2056.3%7D%7B%7B%5Cpi%20%5C%3A%20%5Ctimes%2012%20%5Ctimes%206.73%7D%7D%7D%20)
![d = 0.94 \: cm \: to \: 2d.p](https://tex.z-dn.net/?f=d%20%3D%200.94%20%5C%3A%20cm%20%5C%3A%20to%20%5C%3A%202d.p)
Hence the diameter of the object is 0.94 cm
Answer:
B. 12.8 mL
Explanation:
B is the right answer because the volume of the fluid is <em>12.8</em><em> </em><em>mL</em>