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serg [7]
2 years ago
6

28. If the total pressure of a mixture of four gases (neon, carbon dioxide, oxygen and hydrogen) is 1245 mm

Chemistry
1 answer:
Bingel [31]2 years ago
8 0

Answer:

D) 373 mm Hg.

Explanation:

We can solve this problem by keeping in mind<em> Dalton's law of partial pressures</em>, which states that the total pressure of a mixture of gases is equal to the sum of each gas' partial pressures. In other words, for this case:

  • Total Pressure = Ne Pressure + CO₂ Pressure + O₂ Pressure + H₂ Pressure
  • 1245 mm Hg = Ne Pressure + 145 mm Hg + 228 mm Hg + 499 mm Hg
  • Ne Pressure = 373 mm Hg

The answer is option D) 373 mm Hg.

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How many liters of solution will contain 1.5 moles of CaCl2 if the solution is 6.0 M CaCl2?
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Answer:

0.25

Explanation:

volume= number of moles over concentration

hence v=1.5/6

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3 0
3 years ago
Mr. Chem S. Tree added water to 250. ML of a 2.50 M NaOH solution, until the final volume was 500. ML. What is the new molarity
tresset_1 [31]

Answer:

molarity of diluted solution = 1.25 M

Explanation:

Using,          

C1V1 (Stock solution) = C2V2 (dilute solution)

given that

C1 = 2.50M

V1 = 250ML

C2 = ?

V2 = 500ML

2.50 M x 250 mL = C2 x 500 mL

C2 = (2.50 M x 250 mL) / 500 mL

C2 = 1.25 M

Hence, molarity of diluted solution = 1.25 M

4 0
3 years ago
Calculate the molecular weight of a substance. In which the solution of this substance in the water has a concentration of 7 per
Eduardwww [97]

Answer : The molecular weight of a substance is 157.3 g/mol

Explanation :

As we are given that 7 % by weight that means 7 grams of solute present in 100 grams of solution.

Mass of solute = 7 g

Mass of solution = 100 g

Mass of solvent = 100 - 7 = 93 g

Formula used :  

\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=k_f\times\frac{\text{Mass of substance(solute)}\times 1000}{\text{Molar mass of substance(solute)}\times \text{Mass of water(solvent)}}

where,

\Delta T_f = change in freezing point

T_f^o = temperature of pure water = 0^oC

T_f = temperature of solution = -0.89^oC

K_f = freezing point constant of water = 1.86^oC/m

m = molality

Now put all the given values in this formula, we get

(0-(-0.89))^oC=1.86^oC/m\times \frac{7g\times 1000}{\text{Molar mass of substance(solute)}\times 93g}

\text{Molar mass of substance(solute)}=157.3g/mol

Therefore, the molecular weight of a substance is 157.3 g/mol

7 0
3 years ago
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