Answer:
bottom right, x = 90
bottom left, x = 40
top left, x = 28
Step-by-step explanation:
This problem uses the variable x to mean three different numbers.
This is an incorrect use of a variable.
On the bottom right, x is a right angle, so x = 90.
On the bottom left, x + 5 = 45, so x = 40.
On the top left, 3x + 6 = 90, so x = 28.
Answer:
2309.07 ft
Step-by-step explanation:
The formula for finding volume of a cylinder is V = πr^2*h. You can plug in your radius, which is 7, and your height, which is 15. This gives you 735π, or 2,309.07.
Try this option:
1) the rule 1: if f(x)=u(x)*v(x), then f'(x)=u'(x)*v(x)+u(x)*v'(x), where u(x)=x³, v(x)=ln(cos²x);
2) the rule 2: if f(x)=u(v(x)), then f'(x)=u'(v(x))*v'(x), where u(v(x))=ln(cos²x), v(x)=cos²x;
3) according to the rules above:
f'(x)=(x³)'*ln(cos²x)+x³*(ln(cos²x))';
![f`(x)=3x^2ln(cos^2x)+x^3*\frac{1}{cos^2x}*(-2sinxcosx)=3x^2ln(cos^2x)-2x^3tanx.](https://tex.z-dn.net/?f=f%60%28x%29%3D3x%5E2ln%28cos%5E2x%29%2Bx%5E3%2A%5Cfrac%7B1%7D%7Bcos%5E2x%7D%2A%28-2sinxcosx%29%3D3x%5E2ln%28cos%5E2x%29-2x%5E3tanx.)
<u>Answer:</u> 3x²ln(cos²x)-2x³tanx.
Answer:
around 1.5 sec
Step-by-step explanation:
basically you wanna figure out at what time is the height=0
since h(t) represents height, set it to 0 then solve for t
i believe you might have forgotten the t in the equation so i assumed it was -167t
0=-167t+256
-256=-167t
t=1.53293413174
around 1.5 seconds after it was dropped
alternatively, you could plug the equation into desmos, replacing h(t) with y and t with x and find the x intercept