1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Viktor [21]
2 years ago
10

Two technicians are discussing solder wire repair. Technician A says that electrical tape can be used to cover the joint. Techni

cian B says that heat shrink tubing can be used to cover the joint. Who is correct?
Engineering
1 answer:
Oksanka [162]2 years ago
8 0

Answer:

8282777727e7e87e7e8e88282883

You might be interested in
If Ori gives a friend three reasons for preferring soccer to basketball, that is an algorithm.
irinina [24]

Answer:

False I'm pretty sure sorry If its wrong

3 0
2 years ago
Read 2 more answers
The 30-kg gear is subjected to a force of P=(20t)N where t is in seconds. Determine the angular velocity of the gear at t=4s sta
tatyana61 [14]

Answer:

\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

Explanation:

Previous concepts

Angular momentum. If we consider a particle of mass m, with velocity v, moving under the influence of a force F. The angular  momentum about point O is defined as the “moment” of the particle’s linear momentum, L, about O. And the correct formula is:

H_o =r x mv=rxL

Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =

MO, where MO is the moment of the force F about point O. The equation expressing the rate of change  of angular momentum is this one:

MO = H˙ O

Principle of Angular Impulse and Momentum

The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular  momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:

\int_{t_1}^{t_2}M_O dt = \int_{t_1}^{t_2}H_O dt=H_0t2 -H_0t1

Solution to the problem

For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is I_o =mK^2_o =30kg(0.125m)^2 =0.46875 kgm^2".

If we analyze the staritning point we see that the initial velocity can be founded like this:

v_o =\omega r_{OIC}=\omega (0.15m)

And if we look the figure attached we can use the point A as a reference to calculate the angular impulse and momentum equation, like this:

H_Ai +\sum \int_{t_i}^{t_f} M_A dt =H_Af

0+\sum \int_{0}^{4} 20t (0.15m) dt =0.46875 \omega + 30kg[\omega(0.15m)](0.15m)

And if we integrate the left part and we simplify the right part we have

1.5(4^2)-1.5(0^2) = 0.46875\omega +0.675\omega=1.14375\omega

And if we solve for \omega we got:

\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}

8 0
2 years ago
WHAT IS THIS PLSSSSSS HELP
alekssr [168]

Answer:

It looks like... A machine that reads electric pulse and surge... Not sure though.

Explanation:

8 0
3 years ago
A well-designed product will increase?​
Colt1911 [192]

Answer:

true

Explanation:

A well designed product will increase in sells and in stock.

8 0
1 year ago
At a certain location, wind is blowing steadily at 5 mph. Suppose that the mass density of air is 0.0796 lbm/ft3 and determine t
nlexa [21]

Answer:

The radius of a wind turbine is 691.1 ft

The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m

Explanation:

Given;

power generation potential (PGP) = 1000 kW

Wind speed = 5 mph = 2.2352 m/s

Density of air = 0.0796 lbm/ft³ = 1.275 kg/m³

Radius of the wind turbine r = ?

Wind energy per unit mass of air, e = E/m = 0.5 v² = (0.5)(2.2352)²

Wind energy per unit mass of air = 2.517 J/kg

PGP = mass flow rate * energy per unit mass

PGP = ρ*A*V*e

PGP = \rho *\frac{\pi r^2}{2} *V*e  \\\\r^2 = \frac{2*PGP}{\rho*\pi *V*e} , r=\sqrt{ \frac{2*PGP}{\rho*\pi *V*e}} = \sqrt{ \frac{2*10^6}{1.275*\pi *2.235*2.517}}

r = 210.64 m = 691.1 ft

Thus, the radius of a wind turbine is 691.1 ft

PGP = CVᵃ

For best design of wind turbine Betz limit (c) is taken between (0.35 - 0.45)

Let C = 0.4

PGP = Cvᵃ

take log of both sides

ln(PGP) = a*ln(CV)

a = ln(PGP)/ln(CV)

a = ln(1000)/ln(0.4 *2.2352) = 7.73

The power generation potential (PGP) scales with speed at the rate of 7.73 kW.s/m

5 0
2 years ago
Other questions:
  • Vending machine controller (adapted from Katz, "Contemporary Logic Design") Design and implement a finite state machine that con
    10·1 answer
  • Write a function called pyramid(height) that acceptsa parameter ""height"". It then prints a pyramid of that height
    10·1 answer
  • For an irreversible isothermal process occured in a system with temperature T, which following expression best evaluates the cha
    11·1 answer
  • All sized companies are required to have a written fire prevention plan true or false
    14·2 answers
  • (a) Design a first-order passive high-pass filter with a cutoff frequency of 1000 rad/sec.
    8·1 answer
  • What is a network? I'LL MARK BRAINLEST
    12·2 answers
  • Rosbel or Janette lol baakkaaa
    11·2 answers
  • Safety-in engineering as with everything else is all about trying to maximize or create the hazards involved with what you are d
    6·2 answers
  • 3.
    7·1 answer
  • A Class A fire extingisher is for use on general combustibles such as:​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!