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Mkey [24]
3 years ago
14

An aluminum metal rod is heated to 300oC and, upon equilibration at this temperature, it features a diameter of 25 mm. If a tens

ile force of 1 kN is applied axially to this heated rod, what is the expected mechanical response

Engineering
2 answers:
Natalka [10]3 years ago
5 0

Answer:

It will results in mechanical hardening.

ludmilkaskok [199]3 years ago
5 0

Answer: the metal will experience a strain of approximately 2.037Mpa

This strain is lesser than if the force was applied at room temperature.

This will reduce internal stress and increase some mechanical properties of the aluminum such as mechanical hardening.

Explanation:

Detailed explanation and calculation and comparison with equivalent tensile stretching at ordinary room temperature is compared.

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Hook's law holds good up to. A elastic limit. B. plastic limit. C.yield point. D.Breaking point

3 0
3 years ago
Two small balls A and B with masses 2m and m respectively are released from rest at a height h above the ground. Neglecting air
statuscvo [17]

Answer:

The kinetic energy of A is twice the kinetic energy of B

Explanation:

5 0
3 years ago
For some transformation having kinetics that obey the Avrami equation (Equation 10.17), the parameter n is known to have a value
OleMash [197]

Answer:

t = 25.10 sec

Explanation:

we know that Avrami equation

Y = 1 - e^{-kt^n}

here Y is percentage of completion  of reaction = 50%

t  is duration of reaction = 146 sec

so,

0.50 = 1 - e^{-k^146^2.1}

0.50 = e^{-k306.6}

taking natural log on both side

ln(0.5) = -k(306.6)

k = 2.26\times 10^{-3}

for 86 % completion

0.86 = 1 - e^{-2.26\times 10^{-3} \times t^{2.1}}

e^{-2.26\times 10^{-3} \times t^{2.1}} = 0.14

-2.26\times 10^{-3} \times t^{2.1} = ln(0.14)

t^{2.1} = 869.96

t = 25.10 sec

5 0
3 years ago
The flexural strength or MOR of a ceramic is 310 MPa. A block of the ceramic, which is 20 mm wide, 15 mm high, and 300 mm long,
Alja [10]

Answer:

F=6200\ \text{N}\\

Explanation:

In this problem you need to define the force that acts upon a beam in a 3 point bending problem. I put a picture of the problem taken from Wikipedia:

In this problem the flexural strength is defined with the following formula:

\sigma=\cfrac{3FL}{2bd^2}

where F is the force applied, L the length between the two rods, b the width of the ceramic block and d it's height.

The force is then defined as:

F=\cfrac{2\sigma bd^2}{3L}=6200\ \text{N}

3 0
3 years ago
I. Draw the velocity diagram for the instant shown and determine the velocity of
trapecia [35]

Answer:

?????????????????????????????????????

3 0
3 years ago
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